double every 6 months
in 6 months there would be 250*2 = 500 crickets
in 1 year there would be 500*2 = 1000 crickets
in 1.5 years there would be 1000 *2 = 2000 crickets
in 2 years there would be 2000 *2 = 4000 crickets
Answer:
Factored form: 2x(2x^2+x+1)
Step-by-step explanation:
You're subtracting them. :)
Answer:
t = 22
2t = 45
Step-by-step explanation:
3t = 68
t = 68/3
Answer:
1. 
2.

Step-by-step explanation:
For case 2 the population grows by 170 per year. Therefore for year t=0 its 2000 and t=1 then the population is 2170 and t=2 population is 2340. We can express the sequence as:

We know the difference is d=170 and n=1,2,3....:
Case two can be define by:


Inequality is 6t ≤ 44 and Jim can rent a boat for 7.33 hrs or less
<u>
Solution:</u>
Given that
Maximum amount Jim can spend to rent a boat = $34
Rental cost of boat for 1 hour = $6
Also Jim has a discount coupon for $8 off.
Need to determine possible number of hours Jim could rent a boat.
Let’s assume possible number of hours Jim could rent a boat be represented by variable "t"
Cost of renting boat for 1 hour = 6
So Cost of renting a boat for t hours = t x renting boat for 1 hour = t x 6 = 6t
Also Maximum amount Jim can spend to rent a boat = $34
As Jim has a discount coupon for $8 off, so Total amount Jim can spend to rent a boat = $ 34 + $ 8 = $ 44
So cost of renting a boat for t hours must be less that of equal to Total amount Jim can spend to rent a boat
=> 6t ≤ 44
On solving above equality for "t" we get ,

Hence inequality is 6t ≤ 44 and Jim can rent a boat for 7.33 hrs or less.