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3 years ago

Helppppppp meee plsss

Mathematics

2 answers:

Trava [24]3 years ago

6 0

Answer:

Hypotenuse= 30.4

Step-by-step explanation:

14² + 27² = hypotenuse²

196 + 729 = hypotenuse²

925 = hypotenuse²

$\sqrt{925}$ = hypotenuse

30.4 = hypotenuse

Hope this helps!

77julia77 [94]3 years ago

4 0

30.4 is the correct answer hope this helps

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A tank contains 250 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

VashaNatasha [74]

Answer:

$A(t)=250-210e^{-\frac{t}{50}}$

Step-by-step explanation:

We are given that

Volume,V=250 L

Mass of salt=m=40 g

Brine containing 1 g per liter

Pumped into the tank at the rate=5 L/min

We have to find the number A(t) of grams of salt in the tank at time t.

Rate of change of salt in the tank

$\frac{dA}{dt}=$ Rate in-Rate out

Rate in=5 L/min

Rate out= $\frac{A}{250}\times 5=\frac{A}{50}$ L/min

$\frac{dA}{dt}=5-\frac{A}{50}=\frac{250-A}{50}$

$\int \frac{50dA}{250-A}=\int dt$

$-50ln(250-A)=t+C$

Using the formula

$\int \frac{dx}{x}=ln x$

A=40 and t=0

$-50ln(250-40)=0+C$

$-50ln(210)=C$

Substitute the value

$-50ln(250-A)=t-50ln(210)$

$-50ln(250-A)+50ln(210)=t$

$50ln\frac{210}{250-A}=t$

$t=50ln\frac{210}{250-A}$

$\frac{t}{50}=ln\frac{210}{250-A}$

$\frac{210}{250-A}=e^{\frac{t}{50}$

$\frac{250-A}{210}=e^{-\frac{t}{50}}$

$250-A=210e^{-\frac{t}{50}}$

$A(t)=250-210e^{-\frac{t}{50}}$

8 0

4 years ago

Pablo wrote four division equations with 6 as the quotient. what could have been the four division equations he wrote?

Gennadij [26K]

$\frac{18}{3}=6 \\ \\
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3 years ago

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Answer:

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490 x 12 is 5,880

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3 years ago

Read 2 more answers

The difference between two numbers is 25. The smaller number is 1/6th of the largest number. What is the value of the smaller nu

Over [174]

Difference between x and y is 25
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