Take the derivative with respect to t

the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero

divide by w

we add sin(wt) to both sides

divide both sides by cos(wt)

OR

(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

since 2npi is just the period of cos

substituting our second soultion we get

since 2npi is the period

so the maximum value =

minimum value =
If the length is taken as l , height is taken as h and breadth is taken as b . then
Area of the rectangular prism= 2( (l*b) + (b*h) + (h*l) )
hope that helps
Answer:
56
Step-by-step explanation:
Isolate the variable (x). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 5 from both sides:
13 (-5) = (x/7) + 5 (-5)
13 - 5 = x/7
8 = x/7
Isolate the variable x. Multiply 7 to both sides:
8(7) = (x/7)(7)
8(7) = x
x = 8 * 7
x = 56
56 is your answer for x.
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