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quester [9]
2 years ago
7

Perform the indicated operation (x-4)(x+8)​

Mathematics
2 answers:
Hitman42 [59]2 years ago
6 0

Answer:

<h2>X^2+4X-32</h2>

Step-by-step explanation:

I assume you want to simplify this.

Use distributive property:

x^2+4x−32 should be your answer.

Paul [167]2 years ago
4 0

Answer:

x^2+4x-32

Step-by-step explanation:

(x-4)(x+8)=x^2+8x-4x-32

x^2+4x-32

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Determine whether test point (-6,4) is a solution to the linear inequality x+y_&lt;1
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now, is it true that -2 is lesser than 1? if it's true, is a solution, if is false, is not then
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The ages, in years, of Sharice’s family members are shown. What is the mean absolute deviation of the data set?
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Step-by-step explanation:

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2 years ago
Read 2 more answers
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408

#Define Y:

Y~(11.04,5.7408)

P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291

Hence, the probability of 12 or fewer is 0.8291

b. The  probability that 5 or more fish were caught.

#Using normal approximation:

P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above P(X\geq 5)=0.9968 and a ,P(X\leq 12)=0.7291

P(5\leq X\leq 120\approx P(4.5\leq Y\leq  12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259

Hence, the probability of between 5 and 12 is 0.7259

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3 years ago
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