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3 years ago

Find the missing side of the triangle. Round your answer to the nearest tenth if necessary.

Mathematics

2 answers:

Soloha48 [4]3 years ago

5 0

Answer:

Step-by-step explanation:

pythagoras theorem

a^2+b^2=c^2

8^2+x^2=10^2

64+x^2=100

x^2=100-64

x= $\sqrt{36$

x=6 km

grin007 [14]3 years ago

3 0

Answer:

x = 6km

Step-by-step explanation:

using pythagoras theorem,

x = $\sqrt{10^{2} - 8^{2} }$

= 6km (reject -6, x>0)

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F (x) = x + 3; g(x) = 1/x What is the domain and range of (f • g)

ArbitrLikvidat [17]

The domain of g alone is {x | x ≠ 0}, and the domain of f is all reals. So the domain of (f ◦ g) is the domain of g {x | x ≠ 0}. (f ◦ g)(x) = 1/x + 3. The range of g(x) = 1/x is actually the same as its domain {y | y ≠ 0}. Adding three, the range of f ◦ g is all reals except for 3, {y | y ≠ 3} The line y = 3 is actually an asymptote (horizontal) to the graph of f ◦ g.

8 0

3 years ago

intrastate 70 stretches almost 2 ^ 3 * 5 ^ 2 * 11 miles across the United States. About how many miles long is the interest 70?

marshall27 [118]

(2)^3 * (5)^2 * 11

We use PEMDAS so we have to do the exponents first.

2^3 = 8

5^2 = 25

8 * 25 *11

You then go left to right cause they are all multiplication:

200 *11 = 2200 miles

4 0

3 years ago

Solve |x+2|=10<br> Please help

Anvisha [2.4K]

x = 8, --- 12

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7 0

3 years ago

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Furkat [3]

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2 years ago

You have two biased coins. Coin A comes up heads with probability 0.1. Coin B comes up heads with probability 0.6.However, you a

Andrews [41]

Answer:

The probability that our guess is correct = 0.857.

Step-by-step explanation:

The given question is based on A Conditional Probability with Biased Coins.

Given data:

P(Head | A) = 0.1

P(Head | B) = 0.6

<u>By using Bayes' theorem:</u>

$P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}$

We know that P(B) = 0.5 = P(A), because coins A and B are equally likely to be picked.

Now,

P(Head) = P(A) × P(head | A) + P(B) × P(Head | B)

By putting the value, we get

P(Head) = 0.5 × 0.1 + 0.5 × 0.6

P(Head) = 0.35

Now put this value in $P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}$ , we get

$P(B|Head) = P(Head|B) \times \frac{P(B)}{P(Head)}$

$P(B|Head) = 0.6 \times \frac{0.5}{0.35}$

$P(B|Head) = 0.857$

Similarly.

$P(A|Head) = 0.857$

Hence, the probability that our guess is correct = 0.857.

7 0

3 years ago