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stiks02 [169]
3 years ago
7

Identify a horizontal or vertical stretch or compression of the function by observing the equation of the function .

Mathematics
1 answer:
Anton [14]3 years ago
4 0
Bdbxbcjncnxndnsnns Identify a horizontal or vertical stretch or compression of the function by observing the equation of the function .hdbdbebqb
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What is the value of x?<br>a.14<br>b.17<br>c.27<br>d.34​
Oksi-84 [34.3K]
The answer is B. 17.

All this lines are there to confuse you. All you have to do is solve for x on both lines.

3x-24=x-10 subtract x from both sides
2x-24=10 add 24 to both sides
2x=34 divide both sides by 2
X=17

Hope this helps.
5 0
3 years ago
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Plz help and thank you
Nastasia [14]

Answer:

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Step-by-step explanation:

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ANSWER THIS ALEGBRA QUESTION IF YOU ARE GREAT AT MATH ‼
Eduardwww [97]

Answer:

C) (5, ∞)

General Formulas and Concepts:

<u>Alg I</u>

  • Range is the set of y-values that are outputted by function f(x).

Step-by-step explanation:

According to the graph, we have a horizontal asymptote at y = 5. Therefore, the graph never actually <em>touches/reaches</em> the y-value 5. Therefore, 5 is not included in our range:

(5, ∞) or y ≥ 5

3 0
3 years ago
Which proportion satisfies the geometric mean (altitude) theorem for the triangle? startfraction 2 over h endfraction = startfra
Anna35 [415]

The proportion that satisfies the geometric mean (altitude) theorem for the triangle is 2/h = h/3

<h3>Triangular altitutude theorem</h3>

According to the theorem, the ratio similar sides of a right triangle are equal. From the given diagram, we are to determine the proportion satisfies the geometric mean (altitude) theorem for the triangle.

Taking the ratio of the base to the height, we will have:
MK/KL = KL/KN

Substitute the measure of the sides

2/h = h/3

Hence the proportion that satisfies the geometric mean (altitude) theorem for the triangle is 2/h = h/3

Learn more on mean altitude theorem here; brainly.com/question/10216660

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2 years ago
Solve x/2 + y/3 = 1 for x
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Answer:

Step-by-step explanation:

5 0
3 years ago
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