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3 years ago

In which kind of climate would frost wedging most liekly occur?

Chemistry

2 answers:

Mnenie [13.5K]3 years ago

5 0

The arctic climate most likely

kozerog [31]3 years ago

4 0

A wet climate in which temperatures alternate between below freezing and above freezing.

Hope this helps! Good luck!! :]

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How do you draw a branched carbon chain for trimethylbutane?

juin [17]

Answer:

I think this is how you draw it, but I'm not entirely sure.

Explanation:

Screenshot below:

3 0

2 years ago

calculate the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom?

inessss [21]

Answer:

$\Delta E=E_{final}-E_{initial}$

$\Delta E=-1312[\frac{1}{(n_f^2)}-\frac {1}{(n_i^2 )}]KJ mol^{-1}$

$\Delta E=-1312[\frac{1}{3^2)}-\frac {1}{(1^2 )}]KJ mol^{-1}$

$\Delta E=-1312[\frac{1}{(9)}-\frac {1}{(1 )}]KJ mol^{-1}$

$\Delta E=-1312[0.111-1]KJ mol^{-1}$

$\Delta E=1166 KJ mol^{-1}$

$\frac{=1166,000 \mathrm{J}}{6.022 \times 10^{23} \text { photons }}$

$=193623 \times 10^{-23} \frac {J}{photon}$

$\Delta E=1.93623 \times 10^{-18} \frac {J}{photon}$

$\Delta E=\frac {h\times c}{\lambda} \\\\=\frac {(6.626\times 10^{-34} J s \times 3 \times 10^8 ms^{-1})}{\lambda}$

h is planck's constant

c is the speed of light

λ is the wavelength of light

$\lambda =\frac {h\times c}{\Delta E}\\\\=\frac {(6.626\times10^{-34} J s\times3 \times 10^8 ms^{-1})}{(1.93623\times10^{-18} J/photon)}$

Wavelength

$\lambda =10.3 \times 10^{-8} m \times \frac {(10^9 nm)}{1m} =103 nm (Answer)$

Thus, the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom is 103 nm.

7 0

2 years ago

Which of the following best describes the movement of particles in a solid?

Volgvan

Answer:

Explanation:

particles are frozen and hence will vibrate in their fixed positions

5 0

3 years ago

silicon, tin, and lead are all in the same group. the density of tin is about 7.28 g/cm3 and the density of lead is about 11.34

Sophie [7]

The atom's radius and mass increase from top to bottom. The density of elements from top to bottom also increases in a periodic table.

Density of Sn= Mass of Sn/Volume of Sn

=24.3968/7.28

=3.49 g/ml*ml/cm³

=3.49 g/cm³

It is accurate to assume that the density of Sn will fall between that of Si and lead . the mass number and radius of the atoms increase from group to group as we move from top to bottom in a periodic table.. The density rises because the increase in mass number is greater than the increase in radius. Simply multiplying by the molar mass of the gas allows one to derive the formula for mass density from the formula for number density. Do not forget that the mass is equal to the moles (n) times the molar mass (M). Smaller masses can be measured in grams instead of kilograms (kg), which is the standard SI unit for mass.

To learn more about density please visit:

brainly.com/question/406690

#SPJ4

7 0

1 year ago

Calculate the theoretical yield and percent yield for this experiment

coldgirl [10]

Answer:

A. Theoretical yield of KCl is 36.49g

B. Percentage yield of KCl is 90.4%

Explanation:

The balanced equation for the reaction is given below:

2KCLO3 —> 2KCl + 3O2

Next, we shall determine the mass KClO3 that decomposed and the mass KCl produce from the balanced equation. This is illustrated below:

Molar mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Molar mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g.

From the balanced equation above,

245g of KClO3 decomposed to produce 149g of KCl.

A. Determination of the theoretical yield of KCl. This is illustrated below:

From the balanced equation above,

245g of KClO3 decomposed to produce 149g of KCl.

Therefore, 60g of KClO3 will decompose to produce = (60 x 149)/245 = 36.49g of KCl.

Therefore, the theoretical yield of KCl is 36.49g

B. Determination of the percentage yield of KCl. This can be obtaine as follow:

Actual yield = 33g

Theoretical yield = 36.49g

Percentage yield =..?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 33/36.49 x 100

Percentage yield of KCl = 90.4%

7 0

2 years ago