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podryga [215]
4 years ago
5

Please help quick! Will give brainiest if you are correct!

Chemistry
1 answer:
sveticcg [70]4 years ago
8 0

/the next low tide will be on monday 5th june at 2:30

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The sodium atom loses an electron to form a sodium ion (Na+). Which statement is correct with respect to its atomic radius?
mixer [17]
Its atomic radius increases because there is less electron shielding after the sodium loses one e-.  Sodium is a nonmetal which means it forms an anion. Anions always increase from their original atomic radius
3 0
3 years ago
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assume the given amount of rbf fully dissociates in water. calculate the molarity of a solution if 124.86 g of rbf are dissolved
xeze [42]

Molarity of a solution if 124.86 g of rbf are dissolved into a solution of water that has a final volume of 2.00L is 0.59.

<h3>What is molarity?</h3>

Molarity is used for dilute aqueous solutions held at a constant temperature. In general, the difference between molarity and molality for aqueous solutions near room temperature is very small and it won't really matter whether you use a molar or molal concentration.

MOLARITY = no of moles of solute/volume of soln in litres

No of moles of rbf = 124.6/104.46

= 1.19

Volume of soln = 2

Molarity=1.19/2 = 0.59

Learn more about Molarity here: brainly.com/question/26756988

#SPJ4

5 0
1 year ago
Y Ggg I Ip us Edd u I by
Dimas [21]

Answer:

??

Explanation:

3 0
3 years ago
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If aluminum has a density of 2.7 g/cm³, what is the volume of 2.7 grams of aluminum?​
Lorico [155]

Answer:

Solution Density of aluminium = 2.7 g/Cm 3 In kg/ m 3 = 27 × 1000 10 =2700 kg/ m 3

Explanation:

Not much of one

4 0
2 years ago
0.0145 moles of helium gas are introduced into a balloon so that the volume of the balloon is 2.54 liters. An additional amount
olga_2 [115]

Answer:

4.43L is final volume of the ballon

Explanation:

Avogadro's law of ideal gases states that <em>equal volumes of gases, at the same temperature and pressure, have the same number of molecules</em>.

The formula is:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

Where V and n are volume and moles of the gas in initial and final conditions.

If the initial conditions are 0.0145 moles and 2.54L and final amount of moles is 0.0253moles, final volume is:

\frac{2.54L}{0.0145mol} =\frac{V_2}{0.0253mol}

V₂ = <em>4.43L is final volume of the ballon</em>

6 0
3 years ago
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