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2 years ago

The energy of a photon is 4.23 x 10-17 J. What is the wavelength of the radiation?

Chemistry

1 answer:

Ludmilka [50]2 years ago

7 0

The wavelength of the radiation is 4.7 x 10⁻⁹ m

What is the Einstein's Formula for Energy?

The energy

E is given, from Einstein's formula, as:

E=h⋅ν

Where:

h=6.63×10⁻³⁴Js is Planck's constant;

ν is the frequency.

You can relate frequency and wavelength

λ through the speed of light c as:

c=λ⋅ν

So finally you get:

E=hc/λ

It is given in the question

The energy of a photon is 4.23 x 10⁻¹⁷ J.

Wavelength = ?

λ = hc/E

λ = 6.63×10⁻³⁴x 3 x 10⁸ / 4.23 x 10⁻¹⁷

λ = 4.7 x 10⁻⁹ m

Therefore the wavelength of the radiation is 4.7 x 10⁻⁹ m .

To know more about Einstein's Equation for Energy

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And non-flammable gases Noble gases are that have low chemical

gtnhenbr [62]

Answer:

Noble gases are odorless, colorless, and nonflammable gases that have low chemical reactivity.
The full valence electron shells of these atoms make noble gases extremely stable.
& they are unlikely to form chemical bonds because they have little tendency to gain or lose

electrons.

5 0

2 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

. Which piece of safety equipment is least likely to be at Jerome's lab station? A. Goggles B. A fire extinguisherC. Heat-proof

charle [14.2K]

D a lab coat
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5 0

2 years ago

The isotopic mass of ²¹⁰₈₆Rn is 209.989669amu. When this nuclide decays by electron capture, it emits 2.368 MeV. What is the iso

zaharov [31]

Starting from the radon mass, add the mass of the electron, and subtract the mass attributable to the gamma radiation (931 Mev = 1 amu).

<h3>What is gamma radiation?</h3>

Gamma radiation (gamma rays) refers to the part of the electromagnetic spectrum with the most energy and shortest wavelength. Astrophysicists define gamma radiation as any radiation with an energy above 100 keV. Physicists define gamma radiation as high-energy photons released by nuclear decay.

Using the broader definition of gamma radiation, gamma rays are released by sources including gamma decay, lightning, solar flares, matter-antimatter annihilation, the interaction between cosmic rays and matter, and many astronomical sources. Gamma radiation was discovered by Paul Villard in 1900.

Gamma radiation is used to study the universe, treat gemstones, scan containers, sterilize foods and equipment, diagnose medical conditions, and treat some forms of cancer.

Learn more about gamma radiation

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5 0

1 year ago

How many grams of nitric acid will react completely with a block of iron metal that is 4.5 cm by 3.0 cm by 3.5 cm, if the densit

denpristay [2]

Balance the equation first:

2 Fe+6 HNO3→2 Fe(NO3)3+3H2

Then calculate mass of Iron :

4.5×3.0×3.5 cm3(1 mL1 cm3)(7.87 g Fe1 ml)=371.86 g Fe

Now use Stoichiometry:

371.86 g Fe×(1 mol Fe55.85 g Fe)×(6 mol HNO32 mol Fe)=19.97 mol HNO3

Convert moles of nitric acid to grams

19.97 mol HNO3×(63.01 g HNO31 mol HNO3)=1258.3 g HNO3

7 0

2 years ago

Read 2 more answers