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3 years ago

one digit from the number 9,484,558 is written on each of seven cards. what is the probability of drawing a card that shows 5?

1 answer:

4 0

Possibility or highly chances are that the five is going to get pulled because there are two of the fives and five isn't rare, so from the number 9,484,558 the number that would possibly be picked is one of the fives because there are two of the fives and five isn't rare if there is two of them, so the digit that would probably be pulled is one of the fives

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If x+1=7, what is the value of x2 + 22 +1?

lara31 [8.8K]

Answer:

Step-by-step explanation:

x+1 = 7

Subtract 1 from each side

x+1-1 =7-1

x =6

x^2 + 22 +1

6^2 +22+1

36+22+1

36+23

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3 years ago

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Answer:

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Step-by-step explanation:

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Members of the high school baseball team need to purchase cleats before the season starts. The pitcher paid $70 for his, but the

prohojiy [21]

Answer:

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Step-by-step explanation:

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3 years ago

What is the equation for a circle with a center at (5,-2) and passes through (4,0)?

Kisachek [45]

Step-by-step explanation:

since you said equation I'm assuming it's in terms of x and y Just as a general equation

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3 years ago

When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o

borishaifa [10]

Answer:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

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4 years ago