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Mandarinka [93]
3 years ago
5

28. In 1.2 s, 52 wave crests spaced 0.12 m apart pass a location. What is the frequency of these waves?

Physics
2 answers:
Reptile [31]3 years ago
4 0

Answer:

0.7

Explanation:

Reasoning The distance between adjacent crests is the wavelength l. Since the speed of each wave is v = 3.00 × 108 m/s and the frequencies are known, the relation v = fl can be used to determine the wavelengths. The equation v = fl applies to any kind of periodic wave.

http://demo.webassign.net/ebooks/cj6demo/xlinks/c16-sec1-0002.htm

LenaWriter [7]3 years ago
3 0

Frequency = (number of waves) / (time)

(52waves) / (1.2 sec) = 43.333 Hz.

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liberstina [14]
Is this practically possible? How can a 100kg man fly? Hahaha
3 0
3 years ago
This force will cause the path of the particle to curve. Therefore, at a later time, the direction of the force will ___________
melisa1 [442]

Answer:

have a component along the direction of motion that remains perpendicular to the direction of motion

Explanation:

In this exercise you are asked to enter which sentence is correct, let's start by writing Newton's second law.

circular movement

          F = m a

          a = v² / r

          F = m v²/R

where the force is perpendicular to the velocity, all the force is used to change the direction of the velocity

in linear motion

         F = m a

where the force is parallel to the acceleration of the body, the total force is used to change the modulus of the velocity

the correct answer is: have a component along the direction of motion that remains perpendicular to the direction of motion

8 0
3 years ago
Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object
user100 [1]

For 3 kg mass: <em>F = \lpha ma,a = \frac{F}{m} = \frac{12N}{3kg} = 4\lpha m / s^{2}</em>

For 6 kg mass: <em>F = \lpha ma,a = \frac{F}{m} = \frac{12N}{6kg} = 2\lpha m / s^{2}</em>


Hope this helped, have a great day!~

3 0
3 years ago
A person kicks a ball off of a 50m high cliff with a speed of 10 m/s. How long will it take the ball to hit the ground? * 7 poin
Musya8 [376]

Presumably, the ball is kicked parallel to the ground below the cliff, so its altitude <em>y</em> at time <em>t</em> is

y(t)=50\,\mathrm m-\dfrac12gt^2

where <em>g</em> = 9.80 m/s^2 is the acceleration due to gravity.

The ball hits the ground when <em>y</em> = 0:

0 = 50\,\mathrm m-\dfrac12gt^2

t^2=\dfrac{100\,\mathrm m}g

t=\dfrac{10}{9.80}\,\mathrm s\approx\boxed{3.2\,\mathrm s}

6 0
4 years ago
A microwave oven operates at 2.4 GHz with an intensity inside the oven of 2300 W/m2 . Part A What is the amplitude of the oscill
Tasya [4]

Answer:

The amplitude of the oscillating electric field is 1316.96 N/C

Explanation:

Given;

frequency of the wave, f = 2.4 Hz

intensity of the wave, I = 2300 W/m²

Amplitude of oscillating magnetic field is given by;

B_o = \sqrt{\frac{2\mu_o I}{c} }

where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

I is intensity of wave

c is speed of light = 3 x 10⁸ m/s

B_o = \sqrt{\frac{2*4\pi *10^{-7}*2300}{3*10^8} } \\\\B_o = 4.3899 *10^{-6} \ T

The amplitude of the oscillating electric field is given by;

E₀ = cB₀

E₀ = 3 x 10⁸ x 4.3899 x 10⁻⁶

E₀ = 1316.96 N/C

Therefore, the amplitude of the oscillating electric field is 1316.96 N/C

3 0
3 years ago
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