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jeyben [28]
3 years ago
11

Which set of side lengths form a right triangle?

Mathematics
2 answers:
Deffense [45]3 years ago
7 0

I just took the test and the answer was D

50 in, 48 in, 14 in are the side lengths that form a right triangle

Reil [10]3 years ago
4 0
I just took the test and the answer was D
50 in, 48 in, 14 in are the side lengths that form a right triangle
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The function f(x)=1+1.5ln(x+1) models the average number of free-throws a basketball player can make consecutively during practi
UNO [17]

Answer:

402 days.

Step-by-step explanation:

f(x)=1+1.5ln(x+1)

When f() = 10 we have:

10 = 1 + 1.5ln (x + 1)

ln (x + 1) = (10-1) / 1.5 = 6

x + 1 = e^6

x = e^6 - 1 = 402.4.

8 0
2 years ago
A profit of a football club after a takeover is modeled by p(t) = t3 - 14t2 + 20t + 120, which t is the number of years after th
Bogdan [553]
T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120

Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10

Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)

0 = 3t - 2
2 = 3t
2/3 = t

Plug 2/3 into original equation, this is a maximum. We want the minimum:

0 = t - 5
5 = t

Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
6 0
3 years ago
What's the answer for 0.63
aleksandr82 [10.1K]
What answer are you looking for percents,fraction form, etc ?
6 0
3 years ago
Prime factors of 20 i dont know this question
dem82 [27]

Answer:

 2 x 2 x 5,

Step-by-step explanation:

20 = 1 x 20

        2 x 10

        4 x 5

Factors of 20= 1, 2, 4, 5, 10, 20.

Prime factors are = 2 x 2 x 5,

6 0
3 years ago
Read 2 more answers
Please help me find out the process to find y for the first three questions and tell me what y is
Sliva [168]

Answer:

1. y = 14.718

2. ??

3. y = 39.794°

Step-by-step explanation:

<em>HINT the side we already know and the side we are trying to find, we use the first letters of their names and the phrase "SOHCAHTOA" to decide which function: </em>

SOH...

 Sine: sin(θ) = Opposite / Hypotenuse

...CAH...

 Cosine: cos(θ) = Adjacent / Hypotenuse

...TOA

 Tangent: tan(θ) = Opposite / Adjacent

1. Sine: sin(θ) = Opposite / Hypotenuse

sin(42°) = y / 22

so on your calculator enter 42 then sin = 0.669

0.669 = y/22      multiply both sides by 22 to get y

y = 14.718

2. is there any other information??

3. The two sides we know are Opposite 40 and Adjacent 48.

SOHCAHTOA tells us we must use Tangent.

Calculate Opposite/Adjacent = 40/48 = 0.833

Find the angle from your calculator using tan-1

Tan y° = opposite/adjacent = 40/48 = 0.833  

tan-1 of 0.833 = 39.794°

7 0
3 years ago
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