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Lostsunrise [7]
3 years ago
7

If AB =CD, CD = 9in, BC = 5x, and AD = 53 in. , find x.

Mathematics
2 answers:
Inessa05 [86]3 years ago
3 0

Answer:

Step-by-step explanation:

U right it’s not any of them and if u single I’m here

Ivahew [28]3 years ago
3 0

Answer:

B.

Step-by-step explanation:

AD, the entire segment, is composed of the three segments AB, BC, and CD. In other words:

AD=AB+BC+CD

Since AB=CD, we can substitute:

AD=CD+BC+CD\\ AD=2CD+BC

We know that CD is 9 and BC is 5x. AD is 53. So, substitute:

53=2(9)+5x

Solve for x:

\begin{aligned} 53&=18+5x \\ 35&=5x \\ 7&=x \end{aligned}

The value of x is 7.

Hence, our answer is B.

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A grocer bought n eggs at $x each. He marked up the price of each egg by $y and sold all of them. Find the sales amount, express
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Answer:

Sales = n \times ($x + $y)

Step-by-step explanation:

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Here in the given question,

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(Markup refers to the profit added to cost)

Thus price = $x (cost) + $y (markup)

Sales = n \times ($x + $y)

Sales amount is the total amount received from sales of products, total quantity at some price provided.

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3 years ago
I. A rhombus is a special type of square. II. A rectangle is a special type of rhombus. III. A trapezoid is a special type of pa
Kobotan [32]

Answer: I. only

--------------------------------------------------------------------------------------------------------------

Explanation :

II. False. a rectangle is a special type of rhombus since a rhombus has all sides equal, while a rectangle has all angles equal. A rhombus has opposite angles equal, while a rectangle has opposite sides equal.  The diagonals of a rhombus intersect at equal angles, while the diagonals of a rectangle are equal in length.

I.  True. A square is a special case of a rhombus, because it has four equal-length sides and goes above and beyond that to also have four right angles. Every square you see will be a rhombus, but not every rhombus you meet will be a square.

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4 0
3 years ago
Leena walked 2/3 of a mile What is 2/3 written as a sum of unit fractions with the denominator of nine
aliya0001 [1]
Bear in mind that multiplying anything, and anything whatsoever by 1, has a product of the anything itself.

so, let's multiply 2/3 by 1 then and check about,

\bf \cfrac{same}{same}=1\qquad thus\cfrac{2}{3}\cdot 1\implies \cfrac{2}{3}\cdot \cfrac{3}{3}\implies \cfrac{6}{9}
\\\\\\
\textit{now, we can split that and write it as a sum}\implies \cfrac{1+5}{9}\implies \cfrac{1}{9}+\cfrac{5}{9}
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3 years ago
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Agata [3.3K]

I am pretty sure the answer is D, but I'm not 100% sure

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2 years ago
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