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3 years ago

If AB =CD, CD = 9in, BC = 5x, and AD = 53 in. , find x.

Mathematics

2 answers:

Inessa05 [86]3 years ago

3 0

Answer:

Step-by-step explanation:

U right it’s not any of them and if u single I’m here

Ivahew [28]3 years ago

3 0

Answer:

Step-by-step explanation:

AD, the entire segment, is composed of the three segments AB, BC, and CD. In other words:

$AD=AB+BC+CD$

Since AB=CD, we can substitute:

$AD=CD+BC+CD\\ AD=2CD+BC$

We know that CD is 9 and BC is 5x. AD is 53. So, substitute:

$53=2(9)+5x$

Solve for x:

$\begin{aligned} 53&=18+5x \\ 35&=5x \\ 7&=x \end{aligned}$

The value of x is 7.

Hence, our answer is B.

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This helicopter has a rotor that moves at a rate of 600 spins per minute while flying. Which statement is supported by this info

jeka57 [31]

Answer: d. The helicopter rotor will spin 36,000 times in 1 hour

Step-by-step explanation:

Option A is wrong because in 40 minutes the rotor will spin:

= 40 * 600

= 24,000 times

Option B is wrong because we cannot know the number of times the rotor will spin before being lifted off of the ground with the details given.

Option C is wrong because in 3 hours the rotor will spin:

= 600 * 3 * 60 minutes

= 108,000 times

Option D is correct because in 1 hour the rotor will spin:

= 600 * 1 * 60 mins

= 36,000 times

5 0

3 years ago

Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol

koban [17]

Answer:

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

Step-by-step explanation:

$\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228$

$=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}$

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

4 0

3 years ago

What is area of ths shape

dimaraw [331]

The area is 114 yards

Step-by-step explanation:

(10x9) + (4x6)

8 0

2 years ago

Read 2 more answers

3y=11-2x, 3x=y-11 linear equation solve using the algebraic method check solution

tamaranim1 [39]

Answer:

(x, y) = (- 2, 5)

Step-by-step explanation:

given the 2 equations

3y = 11 - 2x → (1)

3x = y - 11 → (2)

Rearrange (2) expressing y in terms of x

add 11 to both sides

y = 3x + 11 → (3)

Substitute y = 3x + 11 into (1)

3(3x + 11) = 11 - 2x

9x + 33 = 11 - 2x ( add 2x to both sides )

11x + 33 = 11 ( subtract 33 from both sides )

11x = - 22 ( divide both sides by 11 )

x = - 2

Substitute x = - 2 in (3) for corresponding value of y

y = (3 × - 2) + 11 = - 6 + 11 = 5

As a check

substitute x = - 2, y = 5 into (1) and (2) and if the left side equals the right side then these values are the solution.

(1) : left side = (3 × 5) = 15

right side = 11 - (2 × - 2) = 11 + 4 = 15 ⇒ left = right

(2) : left side = (3 × - 2 ) = - 6

right side = 5 - 11 = - 6 ⇒ left = right

solution = (- 2, 5 )

5 0

3 years ago

You and five of your friends like to go to McDonalds once a week and get Happy Meals for the prize inside. McDonalds has just st

Pavel [41]

Answer:

The most suitable experimental simulation to find the probability of getting the six toys is by rolling the dice and recording the occurrences.

Step-by-step explanation:

As there are a total of 6 different dinosaurs, the probability of each of them is given as

P(X=one dinosaur)=1/6

In order to design an experiment, as the data is completely random and unknown, thus the experiment is designed such that the probability of individual option is 1/6.

In this regard the most suitable option is rolling a dice, numerous times and recording the occurrences accordingly.

8 0

3 years ago