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aliya0001 [1]
2 years ago
9

Find the area of the circle.

Mathematics
2 answers:
mario62 [17]2 years ago
6 0
The area is 28.26
to find the radius you have to divide the diameter by 2 which you’ll get 3
then plug it into the equation
A=3.14•3^2
timama [110]2 years ago
4 0
I’m pretty sure it’s 28.26
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8p + 2q = -16<br> 2p - q=2
yKpoI14uk [10]

Answer:

p = -1  q = -4

Step-by-step explanation:

a system of eq and solve for p and q ???  can do  :)

Eq. 1)  8p + 2q = - 16

Eq. 2)  2p - q = 2

use Eq .2 and solve for q

2p - 2 = q

plug into Eq.1 with q

8p +2(2p - 2) = - 16

8p +4p -4 = -16

12p = - 12

p = -1

plug -1 into Eq. 1 for p and solve for q

8(-1) + 2q = - 16

-8 + 2q = - 16

2q = -8

q = -4

8 0
3 years ago
What is the value of m in the ecuation 1/2m -3/4n = 16, when n =8 ?
soldi70 [24.7K]

Answer: m=44

Step-by-step explanation:

1/2m-3/4n = 16

1/2m-3/4(8) = 16

1/2m-24/4 = 16

1/2m-6 = 16

1/2m = 22

m=44

8 0
1 year ago
The Census Bureau says that the 10 most common names in the United States are (in order) Smith, Johnson, Williams, Jones, Brown,
scZoUnD [109]
Using binomial distribution where success is the appearing of any of the top 10 most common names, thus probability of success (p) is 9.6% = 0.096 and the probability of failure = 1 - 0.096 = 0.904. Number of trials is 11.
Binomial distribution probability is given by P(x) = nCx (p)^x (q)^(n - x)
Probability that none of the top 10 most common names appears is P(0) = 11C0 (0.096)^0 (0.904)^(11 - 0) = (0.904)^11 = 0.3295
Thus, the probability that at least one of the 10 most common names appear is 1 - 0.3295 = 0.6705

Therefore, I will be supprised that none of the names of the authors were among the 10 most common names given that the probability that at least one of the names appear is 67%.
6 0
2 years ago
Which of the following values are in the range of the function graphed below?
slava [35]
The range is the output or the y values in the case of this function. The only y value on this function is 1 therefore the range is 1
5 0
3 years ago
Read 2 more answers
If the ratio of corresponding segments is 2:3, then the ratios of the areas and volumes are
kobusy [5.1K]

Answer:

4:9

Step-by-step explanation:

Area is squaring and Volume is cubing

So it'd be 2^2:3^3, or 4:9

I hope this helped and have a good rest of your day!

6 0
3 years ago
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