The closest answer is
Alpha - mass of 4 and charge of +2; beta - no mass and charge of -1; gamma - no mass and no charge (consists of energy)
It’s not exactly correct because a beta particle has the (small) mass of an electron (also the positron). All other choices are way off, I’d go with this one.
Answer:
Man look this stuff up everybody here brain dead
Explanation:
The final magnification will be 400-fold or 400 times the original size of the object.
For magnifying smaller objects, a compound microscope is used.
A compound microscope consists of an objective and an eyepiece, whose diagram is shown in the adjoining image.
The lens near the object is called an objective and the other one is the eyepiece.
Let the magnification of the objective be m1
Let the magnification of the eyepiece be m2
The final magnification by the microscope, M, will be
M = m1 x m2
Putting the values in the above equation
M = 40 x 10
M= 400
Thus, the final magnification will be 400-fold or 400 times the original size of the object.
To know more about "optical instruments", refer to the link given below:
brainly.com/question/13276240?referrer=searchResults\
#SPJ4
Answer:
1 ) Warm air
2) Cold air
3) Cold water
4) Steel
5) Hot molten
Explanation:
In order to solve this problem, we have to warn that the sound propagates more easily in denser media, in this way we have to identify the densities of the different materials.
Density cold air = 1.2 [kg/m^3]
Density warm air = 1.01 [kg/m^3]
Density cold water = 1000 [kg/m^3]
Density steel = 7500 [kg/m^3]
Density hot molten = 14100 [kg/m^3]
Therefore in order from the slowest to the fastest:
1 ) Warm air
2) Cold air
3) Cold water
4) Steel
5) Hot molten
Answer:
a) Slow down
b) Decreasing.
Explanation:
a) The energy that is converted to heat can be written as:
As the resistance increases, with constant voltage, the amount of power dissipated as heat decreases (less current trought the resistor).
Then, we can conclude that, as the energy dissipated by the resistor is less as its resistance is increased, the heating process will slow down.
b) We have to evaluate what happens with the resistivity of the resistor during the heating.
We know that resistivity of a nichrome wire increases with the temperature. With the conclusion of the previous question, if the resistivity increases and the voltage stays constant, the current in the circuit will decrease as the resistor became hotter.
We can conclude this using the Ohm's law: