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3 years ago

Please help but only answer if u know it!

Mathematics

2 answers:

Setler79 [48]3 years ago

8 0

Step-by-step explanation:

$\frac{ {7}^{4} }{ {7}^{ - 3} } = {7}^{4 - - 3} = {7}^{4 + 3} = {7}^{7}$

ASHA 777 [7]3 years ago

5 0

Answer:

7 to the power of 4 / 7-3

Step-by-step explanation:

You might be interested in

Solve for x in x²+8x+15=0 in factorisation method

Genrish500 [490]

Answer: $x=-5, -3$

Step-by-step explanation:

$x^2 +8x+15=0\\\\(x+5)(x+3)=0\\\\x=-5, -3$

7 0

2 years ago

In the diagram shown at left, three lines intersect to form a triangle. What is the value of x?

Phoenix [80]

Answer:

39°

Step-by-step explanation:

For a straight line, the sum of angle is 180°

At the point where we have the 107°, the inner angle in the triangle will be 180-107=73°

68° is alternate angle to the inner angle in the triangle

Since the sum of angles in a triangle are 180°, then angle x will be

X=180-73-68=39°

Therefore, missing angle is 39°

5 0

3 years ago

By rounding to 1 significant figure , estimate 40.73 x 1.06 Anyone know?

suter [353]

ANSWER: 40

EXPLANATION:

1) 40.73 to 1 significant figure = 40.

2) 1.06 to 1 significant figure = 1.

3) Therefore, we just multiply 40 by 1, which equals 40.

FURTHER EXPLANATION (IF NEEDED):

With significant figures, whole numbers such as 10, 20, 50 etc. have 1 significant figure. This is because the 0 does not count as a significant figure.

With decimals, all numbers after the decimal point are also included as significant figures (even 0). E.g. 40.73 has 4 significant figures and 1.06 has 3 significant figures.

EXAMPLES (IF NEEDED):

Rounding to 2 significant figures:

40.73 = 42
1.06 = 1.1

Rounding to 3 significant figures:

40.73 = 40.7
1.06 = 1.06 (because it's already in 3 significant figures)

Rounding to 4 significant figures:

40.73 = 40.73 (already in 4 significant figures)
1.06 = 1.060 (0 is counted as a significant figure if there is a decimal or another number comes after that 0)

E.g. 1006 has 4 sig figs, while 1060 would have 3 sig figs because the last 0 is not counted as a significant figure. 10.60 would have 4 sig figs because of the decimal.

8 0

3 years ago

The Alvin Secretarial Service procures temporary office personnel for major corporations. They have found that 60% of their invo

Hoochie [10]

Answer:

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

Step-by-step explanation:

For each invoice, there are only two possible outcomes. Either they are paid within 10 working days, or they are not. The probability of an invoice being paid within 10 working days is independent of other invoices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

60% of their invoices are paid within ten working days.

This means that $p = 0.6$

A random sample of 18 invoices is checked.

This means that $n = 18$

What is the probability that at least 6 of the invoices will be paid within ten working days?

Either less than 6 are paid within 10 working days, or at least 6 are paid. The sum of the probabilities of these events is 1. So

$P(X < 6) + P(X \geq 6) = 1$

We want $P(X \geq 6)$ . So

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{18,0}.(0.6)^{0}.(0.4)^{18} \approx 0$

$P(X = 1) = C_{18,1}.(0.6)^{1}.(0.4)^{17} \approx 0$

$P(X = 2) = C_{18,2}.(0.6)^{2}.(0.4)^{16} \approx 0$

$P(X = 3) = C_{18,3}.(0.6)^{3}.(0.4)^{15} = 0.0002$

$P(X = 4) = C_{18,4}.(0.6)^{4}.(0.4)^{14} = 0.0011$

$P(X = 5) = C_{18,5}.(0.6)^{5}.(0.4)^{13} = 0.0045$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0 + 0 + 0 + 0.0002 + 0.0011 + 0.0045 = 0.0058$

Finally

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.0058 = 0.9942$

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

6 0

4 years ago

What is the relationship between the volumes of the cylinder, the cone and the sphere?

musickatia [10]

What is the relationship between the volume of the sphere and the volume of the cylinder? (Answer: The sphere takes up two-thirds of the volume of the cylinder.) What is the relationship between the volume of the cone and the volume of the cylinder? (Answer: The cone takes up one-third of the volume of the cylinder.)

3 0

3 years ago

Read 2 more answers