Answer:
19-12=7, so 4-7=-3, so b is equal to 19
Step-by-step explanation:
the volume of a cube is
side³.
since the volume is 27 m³, the individual side lengths are then the cubic root of 27 = 3 m.
the surface area is 6 squares of 3×3 = 9m², so in total
9 × 6 = 54 m²
The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
<h3>Quadratic equation</h3>
8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
- Using completing the square
8(x² + 2x + 1) = -3 + 8
8(x² + 1) = 5
(x² + 1) = 5/8
- Taking the square root of both sides
(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
Learn more about quadratic equation:
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To find the missing angle first we need to fill in the other angles.
If we look at the 128 its on a straight line that is separated by another straight line so to get the angle on the other side of the line we need to subtract 128 from 180 which is 52.
The same goes for 160 so 180-160 = 20
And again the same for 60 so 180-60 = 120
So now that we have 2 out of 3 angles in the triangle we can figure out the final one by subtracting 120 and 20 from 180 (because theres 180 degrees in a triangle) which equals 40
Now if we look at the 40 degrees the other side is its opposite which makes it the same degree, and now we once again have 2 out of the 3 angles in a triangle so go to the triangle with 52 degrees and 40 degrees and subtract them from 180 which would be 88 degrees.
Now we subtract 88 from 180 to get the missing angle that we need (because its on another straight line thats been separated by another straight line) which equals 92
So the answer to your question is 92 degrees
Step 1:
Calculate the measure of angle ∠ABC



From the triangle in the question,

Step 2:
Calculate the value of AB using the cosine rule below

By substituting the values, we will have
![\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%5E2%3Da%5E2%2Bc%5E2-2%5Ctimes%20a%5Ctimes%20c%5Ctimes%5Ccos%20B%20%5C%5C%20b%5E2%3D10%5E2%2B15%5E2-2%5Ctimes10%5Ctimes15%5Ctimes%5Ccos%20115%5E0%20%5C%5C%20b%5E2%3D100%2B225-300%5Ctimes%28-0.4226%29%20%5C%5C%20b%5E2%3D325%2B126.78%20%5C%5C%20b%5E2%3D451.78%20%5C%5C%20%5Ctext%7BSquare%20root%20both%20sides%7D%20%5C%5C%20%5Csqrt%5B%5D%7Bb%5E2%7D%3D%5Csqrt%5B%5D%7B451.78%7D%20%5C%5C%20b%3D21.26%5Coperatorname%7Bkm%7D%20%5Cend%7Bgathered%7D)
Hence,
The distance of point A to point C is = 21.26km