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rusak2 [61]
3 years ago
8

If 5% sales tax is added to her total, what is the greatest total cost of groceries Darla can spend in order to spend as close t

o $15 as possible without going over?
Mathematics
1 answer:
andrew-mc [135]3 years ago
7 0

Answer:

Approximately $14.20

Step-by-step explanation:

Let the cost of the groceries be represented by c, then;

cost price + VAT = c + (5% of c)

To get the value of the cost, c, that would make him spend as close to $15. Since the tax is 5% of the cost price, then the cost price would be close to $15.

Let c = $14.20, then;

So that,

c + (5% of c) = 14.20 + (5% of 14.20)

                    = 14.20 + 0.71

                    = $14.91

Thus, the greatest total cost of groceries Darla can spend in order to spend as close to $15 as possible is approximately $14.20.

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Read the proposition and the implication shown below. "If the lights are off, there is no one inside." Which statement is a cont
charle [14.2K]
The contrapositive switches the hypothesis and the conclusion and negates both in this form:
Statement: If A, then B
Contrapositive: If not B, then not A. 

In this case, the statement is: 
<span> "If the lights are off, there is no one inside."
Contrapositive:
If there is someone inside, the lights are on. </span>
4 0
2 years ago
In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
Consider a t distribution with 7 degrees of freedom. Compute P(-1.29 &lt; t &lt; 1.29). Round your answer to at least three deci
marusya05 [52]

Answer:

Step-by-step explanation:

Given that there is a t distribution with 7 degrees of freedom.

P(-1.29 < t < 1.29)=1-0.2380

=0.7620

b) Now there is a different t distribution with 18 df.

When P(t\leq c)=0.05

c=-1.733

7 0
3 years ago
A. 15<br> b. 16<br> c. 9<br> d. 14
MAXImum [283]
A. 15
0 +0=0
0 +1 = 1
1+2=3
3+3=6
6+4=10
10+5 = 15
3 0
3 years ago
Read 2 more answers
Beth says that the graph of g(x) = + 1 is a translation of 5 units to the left and 1 unit up of f(x) = . She continues to explai
Nata [24]

Beth's description of the transformation is incorrect

<h3>Complete question</h3>

Beth says that the graph of g(x)=x-5+1 is a translation of 5 units to the left and 1 unit up of f(x) = x. She continues to explain that the point (0,0) on the square root function would be translated to the point (-5,1) on the graph of g(x). Is Beth's description of the transformation correct? Explain

<h3>How to determine the true statement?</h3>

The functions are given as:

g(x) = x - 5 + 1

f(x) = x

When the function f(x) is translated 5 units left, we have:

f(x + 5) = x + 5

When the above function is translated 1 unit up, we have:

f(x + 5) + 1 = x + 5 + 1

This means that the actual equation of g(x) should be

g(x) = x + 5 + 1

And not g(x) = x - 5 + 1

By comparison;

g(x) = x - 5 + 1 and g(x) = x + 5 + 1  are not the same

Hence, Beth's description of the transformation is incorrect

Read more about transformation at:

brainly.com/question/17121698

#SPJ1

7 0
1 year ago
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