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Marysya12 [62]
3 years ago
10

How do scientists classify species?

Physics
2 answers:
insens350 [35]3 years ago
7 0

Answer:

D

Explanation:

serious [3.7K]3 years ago
6 0

Answer:

D. By comparing traits

Explanation:

Because age isn't genetic, as well as names, as well as who discovered, but traits are genetic.  

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Irina rode her bike to work at an average speed of 16 miles per hour. It started to rain, so she got a ride home along the same
KengaRu [80]

Answer:

0.7 hours

Explanation:

From the way back, we can calculate the distance between Irina's work and Irina's home. In fact, we know that the car takes 0.4 hourse traveling at 27 mph, so the distance covered should be

d=vt=(27 mph)(0.4 h)=10.8 mi

When Irina rides to work with her bike, she travels at a speed of 16 mph. So we can find the time she takes by dividing the total distance (10.8 miles) by her speed:

t=\frac{d}{v}=\frac{10.8 mi}{16 mph}=0.7 h

6 0
3 years ago
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During which of the following chemical changes does a precipitate form?
babymother [125]

Answer is B.........

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4 years ago
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A scientist is studying the effect on human health of bacteria that live in the human intestine. In her study, she found that th
irga5000 [103]
70 is the correct awnser
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3 years ago
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The temperatures (in degrees Fahrenheit) in Long Island recorded by the weather bureau over a week were 42, 49, 53, 55, 50, 47,
lora16 [44]

Answer:

Inter Quartile Range

Explanation:

Quartile is a positional statistical average, which divided the data into 4 equal halves.

Q1 (Lower Quartile) has 25% data below it, 75% above it. Q3 (Upper Quartile) has 75% data below it, 25% above it.

Interquartile range is the measure used to calculate how far the lower & upper quartiles are.

7 0
3 years ago
A 2.02 nF capacitor with an initial charge of 4.55 µC is discharged through a 1.22 kΩ resistor. (a) Calculate the current in the
Mandarinka [93]

Answer:

a) 0.048A

b) 0.18µC

c) 1.85A

Explanation:

The discharged current of the capacitor as a function of time is given by:

i=\frac{q_o}{RC}*e^{-\frac{t}{\tau}}\\where:\\\tau=RC\\

\tau=1.22*10^3*2.02*10^{-9}\\\tau=2.46*10^{-6}s

a)

i=\frac{4.55\µC}{2.46\µs}*e^{-\frac{9\µs}{2.46\µs}}\\\\i=0.048A

b)

q=q_o*e^{-\frac{t}{\tau}}

q=4.55\µC*e^{-\frac{8\µs}{2.46\µs}}\\q=0.18\µC

c) the maximum current occurs when t=0

i=\frac{4.55\µC}{2.46\µs}*e^{-\frac{0\µs}{2.46\µs}}\\\\i=1.85A

6 0
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