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GenaCL600 [577]
3 years ago
9

4. Which of the following would be a good reference point to describe the motion of a dog?

Physics
1 answer:
saul85 [17]3 years ago
4 0

ANOTHER RUNNING DOG

Explanation:

In the given question it is to find a suitable reference point to describe  the motion of dog. Here I could suggest that it is better to compare the dog with  another running dog to create the relative speed difference to get a reliable motion variation.

Because the motion of dog is in the linear with respect to the another dog and to the acceleration produced by the dog in the required interval is easy to calculate with respect to  another dog which is already in motion.

Hence, I suggest that Motion of dog can be analysed better by analyse the motion variation of dog with  another dog running.

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. A person weighing 750 N gets on an elevator.
Kobotan [32]

 

F = 750 N  (Force)

d = 10 m  (displacement )

t = 25 s   (time)

L = ?   (Mechanical work )  =  (Energy)

P = ?   (Power)

Solve:

L = F × d = 750 × 10 = 7500 Joules

P = L / t = 7500 / 25 = 300 Watts

5 0
3 years ago
A salt is dissolved in water which has a freezing point of 0 degrees celsius. the freezing point of the solution would be
balandron [24]
A salt is dissolved in water which has a freezing point of 0 degrees celsius. the freezing point of the solution would be dependent on the concentration of the salt in the solution. It is explained by the colligative properties. These <span>are </span>properties<span> that depend upon the concentration of solute molecules or ions, but not upon the identity of the solute. Hope this answers the question.</span>
7 0
3 years ago
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As a solid element melts, the atoms become __________ and they have __________ attraction for one another. more separated, more
galina1969 [7]
The complete statement is 

As a solid element melts, the atoms become more separated and they have less attraction for one another. 

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8 0
3 years ago
A 2011 Porsche 911 Turbo S goes from 0-27 m/s in 2.5 seconds. What is the car's acceleration?
Natalka [10]

Answer:

-10.8m/s^2

Explanation:

a=change in velocity/change in time

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3 0
3 years ago
An open pipe of length 0.39m vibrates in the third harmonic with a frequency of 1400Hz. What is the distance from the center of
Gnoma [55]

Length of the pipe = 0.39 m

Third harmonic frequency = 1400 Hz

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Distance from center  = 0.25 × wavelength

Distance = 0.25 x \frac{2L}{3}

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So, option C is correct.

7 0
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