what is the difference between kinetic energy and random motion of a cylider of oxygen carried by a car and one standing on a pl
1 answer:
Answer:
See explanation below
Explanation:
If we are talking about the kinetic energy of the cylinder of oxygen:
The kinetic energy possessed by any object is given by
where
m is the mass of the object
v is its speed
In this case, we have one cylinder carried by a car and one standing on a platform: this means that the speed of the cylinder carried by the car will be different from zero (and so also its kinetic energy will be different from zer), while the speed of the cylinder standing on the platform will be zero (and so its kinetic energy also zero). Therefore, the kinetic energy of the cylinder carried by the car will be larger than that standing on a platform.
Instead, if we are talking about the kinetic energy due to the random motion of the molecules of oxygen inside the cylinder:
The kinetic energy of the molecules in a gas is directly proportional to the absolute temperature of the gas:
where k is called Boltzmann constant and T is the absolute temperature of the gas. Therefore, we see that K does not depend on whether the gas is in motion or not, but only on its temperature - therefore, in this case there is no difference between the kinetic energy of the cylinder carried by the car and that standing on the platform (assuming they are at the same temperature)
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Explanation:
It is known that relation between velocity and height is as follows.
v =
where, g = acceleration due to gravity = 9.8
h = height = 0.2 m
Therefore, velocity is calculated as follows.
v =
=
= 3.92 m/s
Also,
Putting the given values into the above formula as follows.
=
=
= m/s
or, = m/s
Thus, we can conclude that recoil speed of the Earth is m/s.
With the use of the formula SinФ = nλ / d, there are 16 spectral orders which can be seen when it is illuminated by white light.
Given that a grating has 2000 slits/cm. That is,
d = 0.01 / 2000
d = 5 x m
The wavelength λ = (700 - 400) nm
λ = 300 x m
To calculate how many full spectral orders that can be seen (400 to 700 nm) when it is illuminated by white light, we will use the below formula
SinФ = nλ / d
Φ = (nλ / d)
When n = 1
Φ = (300 x
/ 5 x
)
Φ = 3.4 degrees
when n = 2
Φ = (2 x 300 x
/ 5 x
)
Ф = 6.9 degrees
When n = 3
Ф = (3 x 300 x
/ 5 x
)
When n = 16
Ф = (16 x 300 x
/ 5 x
)
Ф = (0.96)
Ф = 73.7 degrees
when n = 17
Ф = (17 x 300 x
/ 5 x
)
Ф = (1.05)
Ф = Error ( that is, it does not exist)
Therefore, there are 16 spectral orders which can be seen when it is illuminated by white light.
Learn more about double slit here: brainly.com/question/4449144