1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nalin [4]
3 years ago
5

what is the difference between kinetic energy and random motion of a cylider of oxygen carried by a car and one standing on a pl

atform​
Physics
1 answer:
pochemuha3 years ago
6 0

Answer:

See explanation below

Explanation:

If we are talking about the kinetic energy of the cylinder of oxygen:

The kinetic energy possessed by any object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

In this case, we have one cylinder carried by a car and one standing on a platform: this means that the speed of the cylinder carried by the car will be different from zero (and so also its kinetic energy will be different from zer), while the speed of the cylinder standing on the platform will be zero (and so its kinetic energy also zero). Therefore, the kinetic energy of the cylinder carried by the car will be larger than that standing on a platform.

Instead, if we are talking about the kinetic energy due to the random motion of the molecules of oxygen inside the cylinder:

The kinetic energy of the molecules in a gas is directly proportional to the absolute temperature of the gas:

K=\frac{3}{2}kT

where k is called Boltzmann constant and T is the absolute temperature of the gas. Therefore, we see that K does not depend on whether the gas is in motion or not, but only on its temperature - therefore, in this case there is no difference between the kinetic energy of the cylinder carried by the car and that standing on the platform (assuming they are at the same temperature)

You might be interested in
In addition to a reference point you also need distance and __________ to describe location
Lana71 [14]

displacement

btw in not sure

6 0
3 years ago
according to newton's second law of motion of the net force acting on the object increases while the mass of the object remains
Licemer1 [7]

Answer:

The Acceleration will increase

Explanation:

Newton's Second Law of motion: It states that the rate of change of momentum is directly proportional to the applied force and takes places along the direction of the force.

It can be expressed mathematically as,

F ∝ m(v-u)/t

Where (v-u)/t = a

F  = kma.

F = force, m = mass of the body, a = acceleration, k = constant of proportionality which tend to unity for a unit force, a unit mass, and a unit acceleration.

Therefore,

F = ma.

From the equation above,

If the net force acting on a body increase, while the mass of the body remains constant, the acceleration will also increase.

4 0
3 years ago
A rock falls off the edge of a building and falls for 10 seconds. What was
solmaris [256]
Ricks velocity would be zooomin out because it would fall off so strongly so it’d change and it’s weight too
4 0
3 years ago
Read 2 more answers
If it takes 600 N to move a box 5 meters, how much work is done on the box?
Anika [276]

Answer:

<h2>3000 J</h2>

Option C is the correct option.

Explanation:

Given,

Force = 600 N

Distance = 5 meters

Work = ?

Now,

Work = Force \times distance

= 600  \times 5

Calculate the product

= 3000 \: Joule

Hope this helps...

Good luck on your assignment..

3 0
3 years ago
Read 2 more answers
It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
goldenfox [79]

Answer:

B) the change in momentum

Explanation:

Impulse is defined as the product between the force exerted on an object (F) and the contact time (\Delta t)

I=F \Delta t

Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):

I=(ma) \Delta t

However, the acceleration is the ratio between the change in velocity (\Delta v) and the contact time (\Delta t): a=\frac{\Delta v}{\Delta t}, so the previous equation becomes

I=m \frac{\Delta v}{\Delta t}\Delta t

And by simplifying \Delta t,

I=m \Delta v

which corresponds to the change in momentum of the object.

8 0
3 years ago
Other questions:
  • Explain how the gas laws apply to the act of breathing. Describe the changes that occur in each step of the process in terms of
    11·1 answer
  • How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?
    14·1 answer
  • A circuit was set up as shown in the diagram . The tgree resistors are identical
    10·1 answer
  • When are tides lowest? What causes these tides to be lowest?
    11·1 answer
  • Which cekk part is found in a plant cells but not animal cells?
    10·2 answers
  • Stars located near _____ appears to move in circles when viewed from earth
    11·1 answer
  • A lead pellet of mass 10.0g is shot horizontally into a stationary wooden block of mass 100g. The pellet hits the block with an
    13·1 answer
  • Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. what is the approximate vertica
    11·2 answers
  • Can an object be moving downward and have an upward acceleration
    5·2 answers
  • wich statement is true about the law of conservation of energy for an object released from a certain height above the ground​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!