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3 years ago

A ball at the end of a string of 2.2m length rotates at

Physics

2 answers:

Sergio039 [100]3 years ago

4 0

Answer:

The frequency of motion is 5.8 Hz.

Explanation:

frequency of motion of any object is defined as the number of times the object repeats it's motion in 1 second.

mathematically frequency equals $f=\frac{1}{T}$

where,

'T' is the time it takes for the object to complete one revolution. Since it is given that the ball completes 5.8 revolutions in 1 seconds thus the time it takes for 1 revolution equals $\frac{1}{5.8}s$

Hence $T=\frac{1}{5.8}s$

thus the frequency equals

$\frac{1}{\frac{1}{5.8}}s^{-1}\\\\f=5.8s^{-1}=5.8Hz$

Sunny_sXe [5.5K]3 years ago

3 0

Answer:

5.8 Hz.

Explanation:

Given:

The length of the string to which the ball is attached, L = 2.2 m.

The number of revolutions, the ball is making in unit time = 5.8 rev/s.

The frequency of the motion of a rotating object is defined the total number of revolutions the object makes in unit time. It is measured in units of Hertz (Hz) or per second.

It is given that the ball is making 5.8 revolutions in one second, therefore, its frequency of motion would be the same, i.e., 5.8 Hz.

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Explanation:

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For the number we calculated, that is the hundredths place. The 9 in the thousandths place to the right tells us to round the 1 up to a 2.

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