Answer:
3.69 rad/s
Explanation:
From the question given above, the following data were obtained:
Period (T) = 1.7 s
Angular frequency (ω) =?
Thus, we can obtain the angular frequency (ω) by applying the following formula:
ω = 2π/T
Period (T) = 1.7 s
Pi (π) = 3.14
Angular frequency (ω) =?
ω = 2π/T
ω = 2 × 3.14 / 1.7
ω = 6.28 / 1.7
ω = 3.69 rad/s
Thus, the angular frequency of the motion is 3.69 rad/s
answer is the color white
Answer:
The minimum frequency of the coil is 7.1 Hz
Explanation:
Given;
number of turns, N = 200 turns
cross sectional area, A = 300 cm² = 300 x 10⁻⁴ m²
magnitude of magnetic field strength, B = 30 x 10⁻³ T
maximum value of the induced emf, E = 8 V
Maximum induced emf is given as;
E = NBAω
where
ω is angular velocity (ω = 2πf)
E = NBA2πf
where;
f is the minimum frequency, measured in hertz (Hz)
f = E / (NBA2π)
f = 8 / (200 x 30 x 10⁻³ x 300 x 10⁻⁴ x 2 x 3.142)
f = 7.073 Hz
f = 7.1 Hz
Therefore, the minimum frequency of the coil is 7.1 Hz
The answer is (a) because movement is acceleration