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mojhsa [17]
3 years ago
10

In which direction does the sun appear to move across the sky?

Physics
2 answers:
sergiy2304 [10]3 years ago
3 0

Answer:

If we consider a system where the y-axis as the South-North line, and the x-axis as the West-East line (where North and East are the positive sides)

We know that the sun goes from East to West, so in our system, the sun goes from the positive side of the x-axis to the negative side of the x-axis.

Where we would see this if we were standing right in the equator line.

If we where in other point of the planet, the Sun will stil move from East to West, but it will have a little tilt along the path, so we will have a little displacement in the y-axis. This displacement will depend on where we are, if we are at the North of the equator, we will se that the sun seems to go a little towards South as it goes to the West side.

jasenka [17]3 years ago
3 0

Answer:

the sun appears from east to west were it sets

Explanation:

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What is the simplest relationship between the angular wavenumber k and just one of the other kinematic variables?
Inessa [10]

Answer : k=\dfrac{\omega}{k}

Explanation :

The word kinematics means the study of motion. Kinematic variables gives the description of the motion of the body.

Displacement, Velocity, acceleration and time are associated with the motion of particle.

Wavenumber is defined as the frequency of wave, which is measured in cycles per unit distance.

Wave number is also defines as:

k=\dfrac{2\pi}{\lambda}

where, \lambda is wavelength

k=\dfrac{2\pi}{\lambda}\times \dfrac{T}{T}

since, \dfrac{2\pi}{T}=\omega \ and\ \dfrac{1}{V}=\dfrac{T}{\lambda}

So, k=\dfrac{\omega}{V}

Where, \omega is angular frequency and V is velocity of wave.

Hence, the  relationship between the angular wavenumber k and and kinamatic variable V is

k=\dfrac{\omega}{V}

6 0
3 years ago
If a person is walking along at 1.4m/s. How long will it take that person to walk one time around a high school track?​
ratelena [41]

Answer:

285.7s

Explanation:

Given parameters:

Speed of the person  = 1.4m/s

Unknown:

Time it takes to walk one time round the track = ?

Solution:

The circumference of the track is 400m for a standard pitch.

Now;

 Speed  = \frac{distance}{time}

 Time  = \frac{distance }{speed }  

 Now insert the parameters;

Time  = \frac{400}{1.4}  = 285.7s

8 0
3 years ago
Challenge Question (This is supposed to be hard, think critically and take it one step at a time):
aivan3 [116]

Answer:

You must travel at an average speed of 67.06 m/s to be on time to the lecture.

Explanation:

From the question, the total distance from your house to the science lecture is 75 miles.

Also, you get halfway there before you stop for a gas, that is, you have covered half of 75 miles, which 37.5 miles and you also have to cover 37.5 miles to get to the science lecture.

After filling up, you only have 15  minutes before the lecture starts,

To determine how fast you must drive to be on time to the lecture,

we will determine the average speed you need to travel.

From

Average speed = Distance / Time

Distance = 37.5 miles (Convert to meters)

(NOTE: 1 mile = 1609.344 meters)

Hence, 37.5 miles = 37.5 × 1609.344 miles = 60350.4 meters

∴ Distance = 60350.4 meters

Time = 15 minutes (Convert to seconds)

(NOTE: 1 minute = 60 seconds)

Hence, 15 minutes = 15 × 60 seconds = 900 seconds

Now, from

Average speed = Distance / Time

Average speed = 60350.4 m / 900 s

Average speed = 67.06 m/s

Hence, you must travel at an average speed of 67.06 m/s to be on time to the lecture.

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4 years ago
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Atoms of which two elements could combine with atoms of carbon (C) to
Nataly [62]

Answer:

I think the correct answer is (E)

4 0
2 years ago
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