For the part a) we need only the momentum of the box and we have the data to find it.
Momentum is given by,
where clearly, p is the momentum, m the mass of the box and v is the velocity.
Substituting,
For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,
<em>It is the same that part a)</em>
Answer:
Explanation:
1) The time of flight equation for projectile motion can be used here to find total time in air.
t = 2vsin∅ / g
where v is speed, Ф is launch angle
t = 2×4×sin 60 / 9.8
t = 0.71 seconds
2) Distance where it hit the ground is called as range and has the following standard equation
D = v² sin2Ф/g
D = 4²sin 2×60 / 9.8
D = 1.41m
3) Maximum elevation is maximum time reached
h = v² sin²Ф / 2g
h = 4²sin² 60 / 2*9.8
h = 0.61 m
Answer:
x = (mg-f)/k
Explanation:
there are three forces acting on cylinder in a tube, (1) force due to spring = -kx (2) force due to friction = f (3) force due to gravity.
we want to calculate an instant when all three forces acting on mass cancel and there is 0 net force and cylinder momentiraly comes to stop.
let's write it in mathematics.
kx+f-mg=0 (kx is positive because it is upwards and that is how we have setup our coordinate axis in this problem).
solving for x gives.
x = (mg-f)/k.
