Answer:
B= 5,655 m C= 5,890 m.
Explanation:
We are told that the hiker ended up back where she started, so the total displacement was 0.
As displacement is a vector, if the magnitude is 0, this means that their components, along any axis must be 0 too.
If we choose the W-E direction as our x axis (with origin in the start and end point of the travel), being the E direction the positive, and we do the same with the N-S direction (we make it our y axis, with N as positive), we can write the following:
Δx = Δy=0
Next, we sum all the components of A, B and C along x axis, based on the question premises, as follows:
Δx = 1,230 m* cos 36º + B*sin 41º - C*cos 37º =0 (1)
Δy = 1,230 m*sin 36º -B*cos 41º + C* sin 37º = 0
We have a system of 2 linear equations with 2 unknowns (B and C) which can be solved by any suitable method: substitution, sum and substraction, determinants, etc).
Using determinants, we find first the determinant of the unknowns, as follows:
Δ = sin 41º*sin 37º - (-(cos 37º)*(-cos 41º) = -0.208
Now we find the numerator in order to get the value of B, replacing the B column by the independent terms'column:
ΔB = -1230*cos 36º*sin 37º - (-1230*sin 36º*(-cos 37º) = -1,177
⇒ B = ΔB / Δ = -1,177/-0.208 = 5,655 m
Repeating the same process, we get the value for ΔC, as follows:
ΔC = -1230*sin 36º*sin 41º - (-1230*cos 36º*(-cos 41º)) = -1,225
⇒ C = ΔC / Δ = -1,225/-0.208 = 5,890 m
