Which are bones of the middle ear that are responsible for vibrating so sound waves can be passed along?

A car traveling initially at 9.49 m/s accelerates at the rate of 0.988 m/s^2 for 3.05s. What is it’s velocity at the end of the

weeeeeb [17]

Answer:

12.50 m/s

Explanation:

Vi = 9.49 m/s

a = 0.988 m/s²

t = 3.05 s

Vf = ?

Vf = Vi + at

Vf = 9.49 + (0.988)(3.05)

Vf = 12.50 m/s

6 0

3 years ago

Read 2 more answers

What does the term “energy crisis” mean?

Zielflug [23.3K]

An energy crisis<span> is any significant (bottleneck; logistics; or price rise) in the supply of energy resources to an economy. In popular literature, it often refers to one of the energy sources used at a certain time and place, in particular those that supply national electricity grids or those used as fuel in vehicles.</span>

5 0

4 years ago

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?

Natalka [10]

By using the combined gas law which says that P1V1/T1 = P2V2/T2, assuming constant pressure, the volume at the required temperature can be obtained.((0.002 m3)(50+273.15))/(20+273.15) = volume 2 at 50 degrees C.
This gives the answer 0.0022048 m3

5 0

3 years ago

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Three charges, qA is +6.0 μC, qB is –5.0 μC, and qc is +6.0 μC, are located at the corners of a square with each side length at

lesya [120]

The net electric field at point D is determined as 3.95 x 10⁷ N/C.

<h3>Electric field at D due to charge A</h3>

E = kq/r²

where;

r is the distance between A and D
q is charge A

E(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(AD) = 2.16 x 10⁷ i N/C

<h3>Electric field at D due to charge B</h3>

E = kq/r²

where;

r is the distance between A and B
q is charge B

r² = 5² + 5²

r² = 50

r = √50

r = 7.07 cm

E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)

E(BD) = 9 x 10⁶ N/C

in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i N/C

in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j N/C

<h3>Electric field at D due to charge C</h3>

E = kq/r²

where;

r is the distance between C and D
q is charge C

E(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(CD) = 2.16 x 10⁷ j N/C

<h3>Net electric field in x direction</h3>

Ei = 2.16 x 10⁷ i N/C + 6.36 x 10⁶ i N/C

Ei = 2.796 x 10⁷ i N/C

<h3>Net electric field in y direction</h3>

Ej = 2.16 x 10⁷ j N/C + 6.36 x 10⁶j N/C

Ej = 2.796 x 10⁷ j N/C

<h3>Resultant electric field at D</h3>

E = √Ei² + Ej²

E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]

E = 3.95 x 10⁷ N/C

Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.

Learn more about electric field here: brainly.com/question/14372859

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7 0

2 years ago

A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/

KatRina [158]

Complete Question

A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends

25.0 min eating lunch and buying gas

What is the total distance traveled over the entire trip (in km)

Answer:

The value is $D = 139.02 \ km$