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Sav [38]
3 years ago
14

You have 2.394 x 102 mL of oxygen gas (O2) at 7.20 x 102 mm of Hg and 78 oC.

Chemistry
1 answer:
igomit [66]3 years ago
3 0
We are given with
V = <span>2.394 x 102 mL 
P = </span><span>7.20 x 102 mm of Hg
T = </span><span>78 oC

We are asked to determine the mass of the sample in milligrams
Using the ideal gas law
n = PV / RT
n = </span>7.20 x 102 mm of Hg (2.394 x 102 mL) / R (78 + 273)
Use the appropriate value for R or just convert the values to SI and use R = 8.314
Then, solve for the mass of the sample by using the MW Oxygen which is 16 g/mol
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