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avanturin [10]
4 years ago
9

How many gallons of a 60​% antifreeze solution must be mixed with 70 gallons of 25​% antifreeze to get a mixture that is 50​% ​a

ntifreeze? Use the​ six-step method.
Chemistry
1 answer:
Neporo4naja [7]4 years ago
6 0

Answer:

The answer to your question is 175 gallons

Explanation:

Data

60% antifreeze solution  volume = ? = x

25% antifreeze solution   volume = 25%

Final concentration 50%

Process

              0.6x + 0.25(70) = 0.5(70 + x)

Simplification

              0.6x + 17.5 = 35 + 0.5x

              0.6x - 0.5x = 35 - 17.5

                          0.1x = 17.5

                              x = 17.5/0.1

Result

                              x = 175 gallons

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Use the ICE approach

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I         0.0972           0.0486
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Using Raoult's Law,
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[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
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0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
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