Explanation:
It is given that,
Displacement of the delivery truck, 
(due east)
Then the truck moves, 
(due south)
Let d is the magnitude of the truck’s displacement from the warehouse. The net displacement is given by :
d = 4.03 km
Let 
is the direction of the truck’s displacement from the warehouse from south of east.
So, the magnitude and direction of the truck’s displacement from the warehouse is 4.03 km, 37.4° south of east.
The number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
<h3>
Average daily power consumption</h3>
The average daily power consumption is the amount of electric energy consumed by an individual on a daily rate.
The average daily power consumption of individuals in USA is 12,100 W-hr.
<h3>Converting watts to kilowatts</h3>
E = 12,100 Whr/1000
E = 12.1 kWh
Thus, the number of kilowatts used by an individual to operate his appliances is determined as 12.1 kWh.
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The self-inductance of a coil will change by 8 times its original value by increasing its radius value by 2 and increasing the length of the coil by 2.
Self-Inductance: -
The definition of self-inductance is the induction of a voltage in a wire that carries current when the current in the wire is changing. In the instance of self-inductance, the circuit itself induces a voltage through the magnetic field produced by a changing current.
We know that the self-inductance of the coil is denoted by: -
L= µ *π*(r)^2*(N)^2*l
Where
L= Self-Inductance of the coil
µ= Magnetic Permeability Constant
r= Radius of the coil
l= Length of the coil
N= Number of turns of the coil
Here Self-inductance of the coil is directly proportional to the length of the coil and the square of the radius of the coil.
So,
On increasing the radius of the coil by a factor of 2 and the length of the coil by 2 the self-inductance of the coil increases by 8 times its original value.
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a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J
b.) K 2 +GmM( r 11− r 21)=6.9×10 7 J
Applying Law of Energy conservation :
K 1+U 1
=K 2+U 2
⇒K 1− r 1GmM
=K 2− r 2 GmM
where M=5.0×10 23kg,r1
=> R=3.0×10 6m and m=10kg
(a) If K 1
=5.0×10 7J and r 2
=4.0×10 6 m, then the above equation leads to
K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J
(b) In this case, we require K 2
=0 and r2
=8.0×10 6m, and solve for K 1:K 1
=K 2 +GmM (r 11− r 21)=6.9×10 7 J
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Answer:
speed and acceleration
Explanation:
speed is a scalar quantity
acceleration is a vector quantity
