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melisa1 [442]
3 years ago
6

Using diagram 1.1 and diagram 1.2, compare the number of turn of the coils, the pattern of the iron fillings and the angle of de

flection of the ammeter pointer

Physics
1 answer:
miss Akunina [59]3 years ago
3 0

Answer:

The number of turns in the second coil is more than the coil 1.

Explanation:

The magnetic field lines are the imaginary path on which an isolated north pole moves if it is free to do so.

The tangent at any point to the magnetic field line, gives the direction of magnetic field at that point.

More be the crowd ness of magnetic field lines more is the strength of magnetic field.

Here the crowd ness of magnetic field lines is more in figure 2 , so the magnetic filed in figure 2 is more than 1. It shows that the number of turns in the second coil is more than the 1 and also the current in the coil 2 is more than 1 .

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Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen
xxTIMURxx [149]

Answer:

A) first laser

B) 0.08m

C) 0.64m

Explanation:

To find the position of the maximum you use the following formula:

y=\frac{m\lambda D}{d}

m: order of the maximum

λ: wavelength

D: distance to the screen = 4.80m

d: distance between slits

A) for the first laser you use:

y_1=\frac{(1)(d/20)(4.80m)}{d}=0.24m\\

for the second laser:

y_2=\frac{(1)(d/15)(4.80m)}{d}=0.32m

hence, the first maximum of the first laser is closer to the central maximum.

B) The difference between the first maximum:

\Delta y=y_2-y_1=0.32m-0.24m=0.08m=8cm

hence, the distance between the first maximum is 0.08m

C) you calculate the second maximum of laser 1:

y_{m=2}=\frac{(2)(d/20)(4.80m)}{d}=0.48m

and for the third minimum of laser 2:

y_{minimum}=\frac{(m+\frac{1}{2})(\lambda)(D)}{d}\\\\y_{m=3}=\frac{(3+\frac{1}{2})(d/15)(4.80m)}{d}=1.12m

Finally, you take the difference:

1.12m-0.48m=0.64m

hence, the distance is 0.64m

3 0
3 years ago
PLEASEE HELP WILLL GIVE 15+ POINTS AND BRAINLIEST PLEASEEEEEEEEEEEEEEEEEEEEEEE
Dovator [93]

um you can't really get help on this it's mostly you sorry

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