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Vera_Pavlovna [14]
3 years ago
13

Cuales son las disciplinas científicas ayuda plis

Physics
2 answers:
Sergio [31]3 years ago
7 0

Answer:

what?

Explanation:

son4ous [18]3 years ago
4 0
Sorry but No hable espanol?
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We showed that the length of the pendulum of period 2.000 seconds on the Earth’s surface was 0.99396 meters. What period would t
Kitty [74]

To solve this problem it is necessary to apply the concepts related to the Period based on gravity and length.

Mathematically this concept can be expressed as

T= 2\pi \sqrt{\frac{l}{g}}

Where,

l = Length

g = Gravitational acceleration

First we will find the period that with the characteristics presented can be given on Mars and then we can find the length of the pendulum at the desired time.

The period on Mars with the given length of 0.99396m and the gravity of the moon (approximately 1.62m / s ^ 2) will be

T= 2\pi \sqrt{\frac{l}{g}}

T= 2\pi \sqrt{\frac{0.99396}{1.62}}

T = 4.921seg

For the second question posed, it would be to find the length so that the period is 2 seconds, that is:

T= 2\pi \sqrt{\frac{l}{g}}

2= 2\pi \sqrt{\frac{l}{1.62}}

l = 0.16414m

Therefore, we can observe also that the shorter distance would be the period compared to the first result given.

8 0
3 years ago
Acceleration can be defined as the rate at which velocity (blank).
Montano1993 [528]

Rate of change of an object?

6 0
4 years ago
Read 2 more answers
In tae-kwon-do, a hand is slammed down onto a target at a speed of 14 m/s and comes to a stop during the 3.0 ms collision. Assum
GrogVix [38]

Answer:

A) The impulse is 11,7 kg.m/s .  B) The average force on the hand is 3900N

Explanation:

Givens:

Hand's mass (m)= 0,90kg

Hand's initial velocity (vi)= 14m/s

Time of collision (t)= 3ms

<u>A) Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time. We use the formula:</u>

<em />

<em>/F/ = m. /Δv/</em>

<u>Where:</u>

F= Force of Impulse

m= Mass

Δv= change in speed ( vf-vi)

Using that formula we get:

/F/= 0,90kg . / (0m/s-14m/s) /

/F/=0,90kg . 14m/s

<em>/F/ = 11,7 kg. m/s</em>

*note that (vf) is 0 because the hand stops in the action, so it's final

velocity = 0

<u>B)The average force is equal to the change in the momentum over the change in time. We use the formula:</u>

<em>/F/= m. (Δv) : Δt</em>

<u>Where:</u>

F= the average force from the target

m= the mass of the hand

Δv= hange in speed (vf/vi)

Δt= change in time

*if we look closely, we find the we alredy have half of the equation because we have alredy calculated m.(Δv) in point A.

We boil the equation down to:

/F/= Impulse : Δt

/F/= 11,7kg.m/s : 0,003s

<em>/F/= 3900N</em>

*we use 0,003s as our time because the given time was 3ms.

*the final result is expressed in Newtons because our final result ends up beeing <em>kg.m/s²</em> = N

<u />

8 0
4 years ago
The roller-coaster car shown in fig. 6-41 (h1 = 30 m, h2 = 12 m, h3 = 20 m), is dragged up to point 1 where it is released from
maxonik [38]
<span>Since there is no friction, conservation of energy gives change in energy is zero Change in energy = 0 Change in KE + Change in PE = 0 1/2 x m x (vf^2 - vi^2) + m x g x (hf-hi) = 0 1/2 x (vf^2 - vi^2) + g x (hf-hi) = 0 (vf^2 - vi^2) = 2 x g x (hi - hf) Since it starts from rest vi = 0 Vf = squareroot of (2 x g x (hi - hf)) For h1, no hf Vf = squareroot of (2 x g x (hi - hf)) Vf = squareroot of (2 x 9.81 x 30) Vf = squareroot of 588.6 Vf = 24.26 For h2 Vf = squareroot of (2 x 9.81 x (30 – 12)) Vf = squareroot of (9.81 x 36) Vf = squareroot of 353.16 Vf = 18.79 For h3 Vf = squareroot of (2 x 9.81 x (30 – 20)) Vf = squareroot of (20 x 9.81) Vf = 18.79</span>
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The primary source of the Sun's energy is:_________
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The dusting of hydrogen into helium. HOPE THIS HELPEDD
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4 years ago
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