Answer:
it started to move a 1 second
Answer:
3.536*10^-6 C
Explanation:
The magnitude of the charge is expresses as Q = CV
C is the capacitance of the capacitor
V is the voltage across the capacitor
Get the capacitance
C = ε0A/d
ε0 is the permittivity of the dielectric = 8.84 x 10-12 F/m
A is the area = 0.2m²
d is the plate separation = 0.1mm = 0.0001m
Substitute
C = 8.84 x 10-12 * 0.2/0.0001
C = 1.768 x 10-8 F
Get the potential difference V
Using the formula for Electric field intensity
E = V/d
2.0 × 10^6 = V/0.0001
V = 2.0 × 10^6 * 0.0001
V = 2.0 × 10^2V
Get the charge on each plate.
Q = CV
Q = 1.768 x 10-8 * 2.0 × 10^2
Q = 3.536*10^-6 C
Hence the magnitude of the charge on each plate should be 3.536*10^-6 C
The amount of solid does not affect how you are describing the solid so a is the answer
when wave propagate through the medium the medium particles have two type of possible motions
1) Transverse Waves : here medium particles will move perpendicular to wave propagation and they pull and push perpendicular to the length
2) Longitudinal wave : here medium particles will move to and fro along the length of the medium and the medium particles will push and pull together along the length of the string.
So here in two types of wave motion it will depends on the medium type as well as it will depend on the source how is wave produced.
So the given type of wave in which particles push together and pull apart the wave must be longitudinal wave.
My science teacher said that there is no equivalent unit to a newton
