The maximum number of orbits in an atoms is____.<br> A) 3<br> B) 5<br> C) 7<br> D) 9

Heyy guys, so basically i need help with stoichiometric calculation I will give you 100 points just to answer all of these answe

jeka94

Answer:

3. The mass of ethanol required is approximately 0.522869 g

The mass of ethanoic acid required is approximately 0.68156 g

4. The mass of iron (III) oxide required is approximately 285.952.189.095 tonnes

5. The mass of silver nitrate required is approximately 14.53 grams

6. The mass of copper oxide that would be needed is approximately 31.86 grams

7. a. The mass of the precipitate, Zn(OH)₂ formed is approximately 49.712 grams

b. The mass of the precipitate, Al(OH)₃ formed is approximately 13 grams

c. The mass of the precipitate, Mg(OH)₂, formed is approximately 14.579925 grams

Explanation:

3. The 1 mole of ethanol and 1 mole of ethanoic acid combines to form 1 mole of ethyl ethanoate

The number of moles of ethyl ethanoate in 1 gram of ethyl ethanoate, n = 1 g/(88.11 g/mol) = 1/88.11 moles

∴ The number of moles of ethanol = 1/88.11 moles

The number of moles of ethanoic acid = 1/88.11 moles

The mass of ethanol = (46.07 g/mol) × 1/88.11 moles = 0.522869 g

The mass of ethanoic acid in the reaction = 60.052 g/mol × 1/88.11 moles ≈ 0.68156 g

4. 1 mole of iron(III) oxide reacts with 1 mole of CO₂ to produce 1 mole of iron

The number of moles in 100 tonnes of iron= 100000000/55.845 = 1790670.60614 moles

The mass of iron (III) oxide required = 159.69 × 1790670.60614 = 285952189.095 g ≈ 285.952.189.095 tonnes

5. The number of moles of NaCl in 5 grams of NaCl = 5 g/58.44 g/mol = 0.0855578371 moles

The mass of silver nitrate required, m = 169.87 g/mol × 0.0855578371 moles ≈ 14.53 grams

6. The number of moles of CuSO₄·5H₂O in 100 g of CuSO₄·5H₂O = 100 g/(249.69 g/mol) ≈ 0.4005 moles

The mass of copper oxide required, m = 79.545 g/mol × 0.4005 moles ≈ 31.86 grams

7. a. The number of moles of NaOH in the reaction = 20 g/(39.997 g/mol) ≈ 0.5 moles

2 moles of NaOH produces 1 mole of Zn(OH)₂

0.5 moles of NaOH will produce 0.5 mole of Zn(OH)₂

The mass of 0.5 mole of Zn(OH)₂ = 0.5 mole × 99.424 g/mol = 49.712 grams

The mass of the precipitate, Zn(OH)₂ formed = 49.712 grams

b. 6 moles of NaOH produces 2 moles Al(OH)₃

20 g, or 0.5 mole of NaOH will produce (1/6) mole of Al(OH)₃

The mass of the precipitate, Al(OH)₃ formed, m = 78 g/mol×(1/6) moles = 13 grams

c. 2 moles of NaOH produces 1 mole of Mg(OH)₂, therefore;

20 g or 0.5 moles of NaOH formed (1/4) mole of Mg(OH)₂

The mass of the precipitate, Mg(OH)₂, formed, m = 58.3197 g/mol × (1/4) moles = 14.579925 grams

3 0

3 years ago

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Interpret the electron configuration

Svetach [21]

Answer:

Ca for calcium

20 electrons

2-2s electron

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Explanation:

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Write a balanced molecular equation describing each of the following chemical reactions. (a) Solid calcium carbonate is heated a

viktelen [127]

Answer:

a. CaCO₃ (s) → CaO (s) + CO₂(g) ΔH

b. 2C₄H₁₀ (g) + 13O₂(g) → 8CO₂ (g) + 10H₂O(g)

c. MgCl₂ (aq) + 2NaOH(aq) → Mg(OH)₂ (s) ↓ + 2NaCl (aq)

d. 2H₂O(g) + 2Na(s) → 2NaOH(s) + H₂(g)

Explanation:

We identify the compound by the formula and we make the reaction with the phases of each reactant and product:

a. CaCO₃ (s); CaO (s), CO₂(g)

The reaction is: CaCO₃ (s) → CaO (s) + CO₂(g) ΔH

We add the ΔH symbol because there is heat added to the reaction, which means a enthalpy change

b. C₄H₁₀ (g), O₂(g) ; CO₂ (g), H₂O(g)

The reaction is: 2C₄H₁₀ (g) + 13O₂(g) → 8CO₂ (g) + 10H₂O(g)

In order to balance, we add 10 moles to water, so in total we have 20 H. Therefore we need 2 moles of butane to have 20 H, but we also have 8 C. So we need 8 C for the CO₂. By the end we have 16 O in CO₂ plus 10 O from water. In conclussion we need 13 O₂ in the reactant side to get the final balance

c. MgCl₂ (aq), NaOH(aq) ; Mg(OH)₂ (aq) , NaCl

The reaction is: MgCl₂ (aq) + 2NaOH(aq) → Mg(OH)₂ (s) ↓ + 2NaCl (aq)

As the Mg(OH)₂ is solid, it indicates that we made a precipitate in the reaction (That's why we add ↓, in the product side). We need 2NaCl, to balance the Cl and 2 NaOH to balance the Na.

Finally the Mg is balanced

d. H₂O(g), Na(s) ; NaOH (s), H₂(g)

Reaction is: 2H₂O(g) + 2Na(s) → 2NaOH(s) + H₂(g)

We add 2 water in order to balance the hydrogen gas, but we need a 2 in the hydoxide. Finally we will balance the Na with also a 2.

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3 years ago

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laiz [17]

1. The forces make the train float because the poles are the same on each side causing them to repell (north and north repell)

2. B is more stable. If you pushed A it would fall and that would cause more disturbance

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The maximum number of orbits in an atoms is____. A) 3 B) 5 C) 7 D) 9