A will represent Anna. k will represent Kylie.
7a+7k=231
a=9+k
Substitute for a
7(9+k)+7k=231
63+7k+7k=231
14k=168
k=12
Then plug in the k value
a=9+12
a=21
Final answer: Anna=21 mph, Kylie= 12 mph
Answer:
OBTUSE
Step-by-step explanation:
You would first have to figure this put via Pythagorean theroem. Basically do this (attachment)***C IS THE LARGEST NUMBER*** and know that c^2 < a^2 + b^2 (less than) = ACUTE, c^2 > a^2 + b^2 (greater than) = OBTUSE, and c^2 = a^2 + b^2 is RIGHT. If it is Right with all different numbers, it is SCALENE.
1. 73-(23)+24=74
2. (68)+35-35=68
3. 64/4(x)4=64
4. f
5. 5+5+5+5+5
Answer:
(a) true
(b) true
(c) false; {y = x, t < 1; y = 2x, t ≥ 1}
(d) false; y = 200x for .005 < |x| < 1
Step-by-step explanation:
(a) "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...
s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m
This equation matches the form of a function periodic with period 2T.
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(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:
s(a) +s(b) = s(a+b) . . . . definition of linear function
Then if a=b, you have
2s(a) = s(2a)
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(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.
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(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.
