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2 years ago

7

There are 25 students in Ms. Turner's English class, and 5 of them are in the Amazing Apples reading group. What percent of the

students are in the Amazing Apples reading group?

1 answer:

lesya692 [45]2 years ago

5 0

Answer:

20%

Step-by-step explanation:

100 divided by 5 is 20

#so_smart

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The graph of a quadratic function is shown on the grid.

Vinvika [58]

Answer:

D

Step-by-step explanation:

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2 years ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$

So, the approximate equation for P is ...

$P(t)=131.836\cdote^{0.032t}$

And the parameters of interest are ...

k = 0.032
P0 = 131.836

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2 years ago

I’m so confused on how to do this

dimaraw [331]

Answer:

19

Step-by-step explanation:

First: Recognize that (f o g)(x) is the "composition" of two functions, where g(x) serves as the input to f(x). We are given f(x) = 2x+3 and g(x) = x+5. You could find g(3) right now: it is g(3) = 3+5 = 8. Use this 8 as the input to f(x): f(8) = 2(8)+3 = 19.

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3 years ago

Please Answer Quick!!

Alexeev081 [22]

Answer:

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3 years ago

Which story problem is solved using multiplication? Answer options with 5 options

galina1969 [7]

D is the answer because it says each and that’s a key word to understand that it’s multiplying

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3 years ago

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