The work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.
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Work done by friction to prevent the crate from moving</h3>
The work done is determined by applying the principle of conservation of energy.
W = K.E
W = ¹/₂mv²
where;
- m is mass of crate
- v is speed of the crate with respect to the truck = 20 m/s
W = ¹/₂(100)(20²)
W = 20,000 J
Thus, the work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.
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Answer:169.6m/s
Explanation:
Wavelength=32cm=0.32m
Frequency=580Hz
Velocity=frequency x wavelength
Velocity=580x0.32
Velocity=169.6m/s
Answer:
the first one looks like a spiral galixy
the 2nd one looks like a lenticular galixy ?? (im pretty sure but not 100%)
the 3rd one looks like a elliptical galixy
Explanation:
Explanation:
It is given that,
Radius of curvature of the mirror, R = 1.54 cm
(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :
f = focal length of the mirror
f = 0.77 cm
(b) The power of mirror is given by the reciprocal of focal length i.e.
Power, 
P = 1.29 diopters
Hence, this is the required solution.
Answer:
D) Reduce the internal friction of the engine's parts.
Explanation:
To increase the efficiency of the car's engine, an engineer most like has to reduce the friction within the internal engine parts. Reducing these friction reduces the useful energy lost as heat in these internal parts of the engine, when the engine parts do work against friction to move. In most everyday activities, engines and machines, energy is usually lost as heat due to frictional forces arising from two or more surfaces in contact.
