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3 years ago

Do metals gain or lose electrons in order to acquire a full octet

1 answer:

8 0

Metals are just over a full octet, and non-metals just under. It just occurs as metals have 1-3 valence electrons so it is cooler for metals to lose electron than to gain electron for the reason that they would have to get more electrons as likened to losing electrons. So the answer is lose.

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Can a ratio be expressed as a percentage

cupoosta [38]

Yes, ratio can be expressed in percentage.

7 0

2 years ago

Different masses are hung on a spring scale calibrated in newtons. The force exerted by gravity on 1.0 kg is shown in the image

nekit [7.7K]

d.88 n

Explanation:

The force exerted by gravity on the mass is 88N;

Gravitational force is usually experienced by two bodies with masses.

This force causes all objects on earth to accelerate at 9.8m/s².

Force of gravity = mass x acceleration due to gravity

In this case, the force exerted on the object by gravity will be the weight of the object.

Weight is a force applied gravity on a body:

Weight of the masses = Force of gravity = mass x acceleration

Given mass = 9kg

Force of gravity = 9 x 9.8 = 88.2N approximately 88N

learn more:

Weight and mass brainly.com/question/5956881

#learnwithBrainly

5 0

3 years ago

What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use

marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force $F_{1}=18\ N$

Force $F_{2}=26\ N$

Force $F_{3}=14\ N$

We need to calculate the torque due to force F₁

Using formula of torque

$\tau_{1}=-F_{1}d_{1}$

$\tau_{1}=-F_{1}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{1}=-18\times\dfrac{0.2}{2}$

$\tau_{1}=-1.8\ N-m$

We need to calculate the torque due to force F₂

Using formula of torque

$\tau_{2}=F_{2}d_{2}$

$\tau_{2}=F_{2}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{2}=26\times\dfrac{0.2}{2}$

$\tau_{2}=2.6\ N-m$

We need to calculate the torque due to force F₃

Using formula of torque

$\tau_{3}=F_{3}d_{3}$

$\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{3}=0.1(14\sin45+14\cos45)$

$\tau_{3}=1.92\ N-m$

We need to calculate the net torque on the square plate

$\tau=\tau_{1}+\tau_{2}+\tau_{3}$

$\tau=-1.8+2.6+1.92$

$\tau=2.72\ N-m$

Hence, The net torque on the square plate is 2.72 N-m.

3 0

2 years ago

How many centimeters are in 24 meters

aleksandr82 [10.1K]

The answer is 2400 centimeters

5 0

2 years ago

Read 2 more answers

1. How would you expect an instantaneous acceleration vs. time graph to look for a cart moving with a constant

r-ruslan [8.4K]

Answer:

a=0 v = v₀ + a t

a=0 line is horizontal

Explanation:

1, In a graph of acceleration vs. time, we have lines, when the line is horizontal it is zero, when the line has a positive slope the increasing accelerations and when the slope is negative the decreasing acceleration

2, speed and relationship of a car is given by

v = v₀ + a t

where vo is the initial velocity, a is the acceleration and tel time

in this case I will calcograph velocity vs. time the constant acceleration is a straight line.

In general from the graph we can find the initial velocity with the cut at that x and the acceleration of the car with the slope

6 0

3 years ago