Answer:
??
Explanation:
what's the actual question
The volume of the object must be no larger than 
.
Explanation:
In order for an object to be able to float in water, its density must be equal or smaller than the water density.
The density of water is:
This means that the density of the object must be no larger than this value.
We also know that the density of an object is given by
where
m is the mass of the object
V is its volume
For the object in this problem, the mass is
Therefore, we can re-arrange the equation to find its volume:
So, the volume of the object must be no larger than .
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Answer:
1977.696 J
Explanation:
Given;
Weight of the box = 28.0 kg
Force applied by the boy = 230 N
angle between the horizontal and the force = 35°
Therefore,
the horizontal component of the force = 230 × cosθ
= 230 × cos 35°
= 188.405 N
Coefficient of kinetic friction, μ = 0.24
Force by friction, f = μN
here,
N = Normal force = Mass × acceleration due to gravity
or
N = 28 × 9.81 = 274.68 N
therefore,
f = 0.24 × 274.68
or
f = 65.9232 N
Now,
work done by the boy, W₁ = 188.405 N × Displacement
= 188.405 N × 30
= 5652.15 J
and,
the
work done by the friction, W₂ = - 65.9232 N × Displacement
= - 65.9232 N × 30 m
= - 1977.696 J
[ since the friction force acts opposite to the direction of motion, therefore the workdone will be negative]
Answer:
C. 32.7%
Explanation:
% composition = ( mass S / mass H2SO4 ) × 100 = 32.08/ 98.10 × 100 = 32.7 % pls mark brainliest
