Answer:

Explanation:
Given data
Electric potential at point a is Ua=5.4×10⁻⁸J
q₂ moves to point b where a negative work done on it
Required
Electric potential energy Ub
Solution
When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:

Now substitute the given values
So

Answer:
a = 64 ft / s²
Explanation:
The force in a spring is given by Hooke's law
F = -k x
Let's use the initial data to calculate the spring constant
k = F / x
Reduscate to the English system
x = 3 in (1foot/12 in) =0.25 foot
k = 0.3 / 0.25
k = 1.2 lb / foot
Now we can use Newton's second law
F = ma
a = F / m
a = -k x / m
m = w / g
m = 0.3 / 32 = 0.009375
x= 6 in (1foot /12 in)= 0.5 foot
a = - 1.2 0.5 / 0.009375
a = 64 ft / s²
Answer:
Part a)
a = -9.81 m/s/s
Part b)
v = 0
Part c)
v = 9.81 m/s
Part d)

Explanation:
Part a)
During the motion of ball it will have only gravitational force on the ball
so here the acceleration of the ball is only due to gravity
so it is given as

Part b)
As we know that ball is moving against the gravity
so here the velocity of ball will keep on decreasing as the ball moves upwards
so at the highest point of the motion of the ball the speed of ball reduce to zero

Part c)
We know that the total time taken by the ball to come back to the initial position is T = 2 s
so in this time displacement of the ball will be zero



Part d)
at the maximum height position we know that the final speed will be zero
so we will have

here we have


The student's path traces out a rectangle and she ends up at the same spot, so her <u>displacement</u> is 0 m.
On the other hand, she travels a <u>total distance</u> equal to the perimeter of that rectangle,
4.0 m + 8.0 m + 4.0 m + 8.0 m = 24 m