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anzhelika [568]
2 years ago
14

A carbon atom can form 4 covalent bonds how many valence electrons does a carbon atom have?

Physics
1 answer:
frozen [14]2 years ago
8 0
I am 11 year old I just wanted to login in so I don't know the answer
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Show us the pictures I don't see it
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Write down any four points that should be considered during household wiring
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3 years ago
Read 2 more answers
Conservation of Momentum<br> No one likes you little trolls please send an actual answer
Olin [163]

Hello!

This is an example of an inelastic collision, where the two objects "stick" to each other after their collision. (The Goalkeeper CATCHES the puck).

We can write out the conservation of momentum formula:

m1vi + m2vi = m1vf + m2vf

Let:

m1 = mass of puck

m2 = mass of the goalkeeper

We know that the initial velocity of the goalkeeper is 0, so:

m1vi + m2(0) = m1vf + m2vf

m1vi = m1vf + m2vf

The final velocities will be the same, so:

m1vi = (m1 + m2)vf

Plug in the given values:

(0.16)(40)/ (0.16 + 120) = vf ≈ 0.0533 m/s

Using the equation for momentum:

p = mv

The object with the LARGER mass will have the greater momentum. Thus, the Goalkeeper has the largest momentum as p = mv; a greater mass correlates to a greater momentum since the velocity is the same between the two objects. The puck would have a momentum of p = (.16)(0.0533) = 0.008528 kgm/s, whereas the goalkeeper would have a momentum of

p =  (120)(0.0533) = 6.396 kgm/s.

3 0
2 years ago
A train goes up a hill with a 15º incline. If the train has constant speed of 22 m/s, what are the vertical and horizontal compo
Kobotan [32]
Any two-dimensional vector in cartesian (x,y) coordinates can be broken down into individual horizontal and vertical components using trigonometry. If a train goes up a hill with 15 degree incline at a speed of 22 m/s, the horizontal component is 22cos(15)=21.3 m/s and the vertical component is 22sin(15)=5.5 m/s. 
8 0
3 years ago
A ring is attached at the center of the underside of a trampoline. A sneaky teenager crawls under the trampoline and uses the ri
Karo-lina-s [1.5K]

Answer:

Explanation:

Given

Mass of mother m=79\ kg

Mother is released with a speed of v=2.5\ m/s

Assuming we need to find elastic Potential energy stored in Trampoline

Kinetic energy acquired  by Mother comes from Elastic Potential Energy stored in the spring

I.e. Elastic Potential Energy=Kinetic Energy of mother

\frac{1}{2}kx^2=\frac{1}{2}mv^2

E=\frac{1}{2}\times 79\times 2.5^2=246.875\ J

So 246.875 J of Energy is stored in the trampoline as he pull the ring

5 0
3 years ago
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