Answer:
a comet would go faster
Explanation:
the comet is being slingshotted by the suns immense gravitational pull
Answer:
Alain Aspect, David Baltimore, Allen Bard, and Timothy Berners - Lee
Given:
F = ax
where
x = distance by which the rubber band is stretched
a = constant
The work done in stretching the rubber band from x = 0 to x = L is
![W=\int_{0}^{L} Fdx = \int_{0}^{L}ax \, dx = \frac{a}{2} [x^{2} ]_{0}^{L} = \frac{aL^{2}}{2}](https://tex.z-dn.net/?f=W%3D%5Cint_%7B0%7D%5E%7BL%7D%20Fdx%20%3D%20%5Cint_%7B0%7D%5E%7BL%7Dax%20%5C%2C%20dx%20%3D%20%5Cfrac%7Ba%7D%7B2%7D%20%20%5Bx%5E%7B2%7D%20%5D_%7B0%7D%5E%7BL%7D%20%3D%20%20%5Cfrac%7BaL%5E%7B2%7D%7D%7B2%7D%20)
Answer:
Answer: Statement 1 is incorrect.
Reason:
Unit of measure of angular distance is not meters.
Explanation:
The term 'angular size' is used to describe the apparent size of the objects in the night sky.
The angular distance is defined as the angle through which an object moves on a circular path. The SI unit is radian.
Other units are revolution (rev) and degrees.
In statement 1, angular distance is measured in meters which is incorrect. In other options, there is no factual mistake so they are correct.
Let's discuss them,
Statement 2:
Here, we are talking about the use of outstretched hand to estimate the angular distances and sizes which is correct.
Statement 3:
This statement talks about the same angular sizes of the sun and the moon, here the term is again used correctly.
Statement 4:
Here, the angular distance is measured in the correct units i.e, degrees so this statement is also correct.
Answer:
i need the describtion like what i need to do
Explanation:
