Answer:
C
Explanation:
I picked C because the plant is interacting with the sun which is a nonliving part of the environment.
A, B and D are wrong because seaweed, horses, and trees are living things.
Answer:
2.28 × 10^-3 mol/L
Explanation:
The equation for the equilibrium is
CN^- + H2O ⇌ HCN + OH^-
Ka = 4.9 × 10^-10
KaKb = Kw
4.9 × 10^-10 Kb = 1.00 × 10^-14
Kb = (1.00 × 10^-14)/(4.9 × 10^-10) = 2.05 × 10^-5
Now, we can set up an ICE table
CN^- + H2O ⇌ HCN + OH^-
I/(mol/L) 0.255 0 0
C/(mol/L) -x +x +x
E/(mol/L) 0.255 - x x x
Ka = x^2/(0.255 - x) = 2.05 × 10^-5
Check for negligibility
0.255/(2.05 × 10^-5) = 12 000 > 400. ∴ x ≪ 0.255
x^2 = 0.255(2.05 × 10^-5) = 5.20 × 10^-6
x = sqrt(5.20 × 10^-6) = 2.28 × 10^-3
[OH^-] = x mol/L = 2.28 × 10^-3 mol/L
Answer:
The correct option is;
Placing one drop of food coloring in a cup with 60 ml of water at 10°, placing one drop of food coloring in a second cup with 60 ml of water at 40°C
Explanation:
The experimental setup that would allow the student investigate the connection between kinetic energy and temperature should be made up of the following characteristics
1) The constant terms for the experiment should be defined, which in this case are
a) The volume of the water which is 60 ml in both subjects of the experiment
2) The definition of the variable that produces the effect that is being monitored, which is the use of the different temperatures in the two experimental subjects
3)The environmental limits of the experiment, which is the water and the food coloring used
