How many grams of aluminum will react fully with 1.25 moles Cl₂?

Chemistry

1 answer:

Liula [17]2 years ago

3 0

2Al + 3Cl₂ → 2AlCl₃

mol Al = 2/3 x 1.25 = 0.83

mass Al = 0.83 x 27 g/mol = 22.41 g

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