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rosijanka [135]
3 years ago
12

How do I do this? 100 points Please help

Chemistry
2 answers:
Bingel [31]3 years ago
7 0

Answer:

C = 1

CI = 1

Na = 1

Ca = 0

H = 1

O = 0

C = 1

Cl = 2

Hopefully this helps! Feel free to mark brainliest!

harina [27]3 years ago
5 0

Answer:

Explanation:

OK this is simple

i'll try to do the unanswered question

CaCl2

In the table

You look for calcium,Ca you fill 1

THen for Chloride=2

i hope you've understood

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Suppose it took 108 joules of energy to raise a bar of gold from 25 °C to 29.7°C. Given that the specific heat capacity of gold
Lady bird [3.3K]

Answer:

m = 180 g

Explanation:

Given data:

Energy absorbed = 108 J

Mas of gold = ?

Initial temperature = 25°C

Final temperature = 29.7 °C

Specific heat capacity of gold = 0.128 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =29.7 °C - 25°C

ΔT = 4.7 °C

108 J = m ×0.128 J/g.°C ×4.7 °C

108 J = m ×0.60 J/g

m = 108 J/0.60 J/g

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3 0
3 years ago
If the relative activities of two metals are known which metal is more easily oxidized
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Answer: The metal that has a greater reactivity is more easily oxidized.

Explanation:

Oxidation is when the elements lose electrons and increase their oxidation state.

The metals tend to react by losing electrons and form the corresponding cation.

For expample, sodium (an alkalyne metal) loses one elecron and form the cation Na¹⁺ , then this cation combine with an anion and form compounds like NaCl, NaOH. The same do the other alkalyne metals.

Magnesium (an alkalyne earth metal) loses two electrons and form the cation Mg²⁺, then it combines with some anions to form compounds, like MgSO₄, Mg(OH)₂.

So, the easier the metal gets oxidized the greater its reactivity.




6 0
3 years ago
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