Catalysts
a catalyst is something added to a reaction that speeds it up (or lowers the activation energy)
increasing the temp would speed up the whole reaction but not lower the activation energy
so B.
Answer:
2.49 * 10^(-4) m
Explanation:
Parameters given:
Frequency, f = 4.257 MHz = 4.257 * 10^6 Hz
Speed of sound in the body, v = 1.06 km/ = 1060 m/s
The speed of a wave is given as the product of its wavelength and frequency:
v = λf
Where λ = wavelength
This implies that:
λ = v/f
λ = (1060) / (4.257 * 10^6)
λ = 2.49 * 10^(-4) m
The wavelength of the sound in the body is 2.49 * 10^(-4) m.
The answer is C (the same number of valence electrons)
Answer:

Explanation:
The definition of the intensity in terms of power is given by:

Where:
- P is the power
- A is the area
If the sound emits uniformly in all directions and that there are no reflections, we can assume the geometry of the wave sound is spherical.
Let's recall the area of a sphere is 
To the first location we have:

and to the second location we have:

Now, we can divide each intensity to find the second intensity.




I hope it helps you!
Answer:
B. Acidic
Explanation:
Neutral an Basic solutions wouldn't create any reaction