This question is incomplete, the complete question is;
A particle is directed along the axis of the instrument in the figure below. A parallel plate capacitor sets up an electric field E, which is oriented perpendicular to a uniform magnetic field B. If the plates are separated by d = 2.0 mm and the value of the magnetic field is B = 0.60T.
Calculate the potential difference, between the capacitor plates, required to allow a particle with speed v = 5.0 × 10⁵ m/s to pass straight through without deflection.
<em>Hint </em>: ΔV = Ed <em>
</em>
Answer:
the required potential difference, between the capacitor plates is 600 V
Explanation:
Given the data in the question;
B = 0.60 T
d = 2.0 mm = 0.002 m
v = 5.0 × 10⁵ m/s.
since particle pass straight through without deflection.
F
= 0
so, F
= F
qE = qvB
divide both sides by q
E = vB
we substitute
E = (5.0 × 10⁵) × 0.6
E = 300000 N/C
given that; potential difference ΔV = Ed
we substitute
ΔV = 300000 × 0.002
ΔV = 600 V
Therefore, the required potential difference, between the capacitor plates is 600 V
1. Amperes, is the SI unit (also a fundamental unit) responsible for current.
2.
Δq over Δt technically
Rearrange for Δq
I x Δt = Δq
1.5mA x 5 = Δq
Δq = 0.0075
Divide this by the fundamental charge "e"
Electrons: 0.0075 / 1.60 x 10^-19
Electrons: 4.6875 x 10^16 or 4.7 x 10^16
3. So we know that the end resistances will be equal so:
ρ = RA/L
ρL = RA
ρL/A = R
Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper

We are looking for L2 so we can isolate using algebra to get:

If you fill in those values you get 0.0205
or 2.05 cm
Answer:
669042 N upward
Explanation:
= Work done by gravity on pile driver
= Work done by beam
u = Initial velocity
v = Final velocity
m = Mass of pile driver = 2200 kg
g = Acceleration due to gravity = 9.81 m/s²
h = Height the pile driver falls = 4.2 m
d = Bend in beam = 14 cm
Total work done = Change in Kinetic energy

The force the beam exerts on the pile driver while the pile driver is brought to rest is 669042 N upward
Energy =mass*SHC*temp rise
670*0.96*218
=140217.6J
=140.2176KJ
Answer:
This graph shows the distance moved by the train with respect to time
Between t = 3 to t = 5 the train is at rest
Since this graph shows the distance covered by the train so it is a scalar quantity
Explanation:
Here from the graph we can see the distance covered by the train with respect to time
So here from the slope of this graph we can find the speed of the train
Also from t = 3 to t = 5 we can see that slope of the graph is zero
So here n this time interval there is no motion or it is at rest
Now since we know that this is distance vs time graph so it is a scalar quantity showing in this graph