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n200080 [17]
2 years ago
7

A pogo stick has a spring with a force constant of 2.50 × 104 N/m , which can be compressed 11.2 cm. what maximum height, in met

ers above the compressed position of the spring, can a child jump with the stick using only the maximum elastic potential energy in the spring, if the child and stick have a combined mass of 44 kg?
Physics
1 answer:
AleksandrR [38]2 years ago
7 0

Answer:

h = 36.4 cm

Explanation:

given,

spring constant = 2.5 x 10⁴ N/m

compressed distance = 11.2 cm = 0.112 m

mass of the child = 44 kg

maximum height = ?

by energy of conservation

K.E_i +P.E_i= K.E_f + P.E_f

\dfrac{1}{2}kx^2 = mgh

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

156.8 = 44 \times 9.8 \times h

h = \dfrac{156.8}{44 \times 9.8}

h = 0.364 m

h = 36.4 cm

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7 0
3 years ago
You observe two cars traveling in the same direction on a long, straight section of Highway 5. The red car is moving at a consta
Arte-miy333 [17]

Answer:

1)  3.66 s

2) 124.44 m

3) 3.12 s

Explanation:

Let's start by first listing down the information in the question.

Red Car : 34 m/s

Blue Car: 28 m/s

Distance between them : 22 m

The difference in speed between the cars is: 34 - 28 = 6 m/s

This means that the red car is catching up to the blue car at a speed of 6 m/s.

1) We can solve this by just dividing the distance by the difference in speed. This becomes:    \frac{Distance}{Speed}= \frac{22}{6} =   3.66

Thus it takes 3.66 seconds for the red car to catch up to the blue car.

2) We know from (1) that it took 3.66 seconds for the red car to catch up. Since the speed it was travelling at is constant, we only need to multiply it by the time from (1) to get the distance.

This becomes:    Speed * Time = 34 * 3.66 = 124.44

Thus the red car travels 124.44 m before catching up to the blue car.

3) If the red car starts to accelerate the moment we see it, the time taken to get to the blue car will be less than before. We can find this in a simple way.

We can use the motion equation : s = u*t + \frac{1}{2}(a * t^2)

Here s = 22 m

We can take u as the difference in speed. u = 6 m/s

Acceleration a = (2/3) m/s^2

Substituting the these into the equation we get:

22 = 6t + \frac{1}{2}(\frac{2}{3}t^2)

Solving this for the variable 't' using the quadratic formula we get the following two answers:

t1  = 3.12 s

t2 = - 21.12 s

Since t2 is not possible, the answer is t1. This means it takes 3.12 seconds for the red car to catch up to the blue.

4 0
3 years ago
If I turn on a light in a spaceship traveling 1C BACKWARDS, what happens to the photons? Speed -0-, or 1C in opposite direction?
Advocard [28]

If the spaceship's Physicist happens to be hanging out of one side
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When those photons pass somebody who happens to be in their
path, and he decides to measure their speed, he'll see them move
past him at 'c' ... the speed of light.
 
It doesn't matter whether the observer who measures them is
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And it doesn't matter what source the photons come from, or
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And it doesn't matter what the photons' wavelength/frequency is ...
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The photons pass everybody at 'c' ... the speed of light.

Yes, I hear you.  That can't be true. It's crazy.
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5 0
3 years ago
Light of wavelength 520 nm is used to illuminate normally two glass plates 21.1 cm in length that touch at one end and are separ
Oksi-84 [34.3K]

Answer:

The number is  Z = 216 \ fringes

Explanation:

From the question we are told that

      The wavelength is  \lambda  =  520 \ nm =  520 *10^{-9} \ m

       The length of the glass plates is y  = 21.1cm = 0.211 \ m

      The distance between the plates (radius of wire ) =  d =  0.028 mm  =  2.8 *10^{-5} \  m

   Generally the condition for constructive  interference in a film is mathematically represented as

            2 *  t  = [m +  \frac{1}{2}  ]\lambda

Where  t is the thickness of the separation between the glass i.e  

    t  = 0 at the edge where the glasses are touching each other and  

     t =  2d at the edge where the glasses are separated by the wire  

   m is the order of the fringe it starts from  0, 1 , 2 ...

So  

       2 *  2 * d   = [m +  \frac{1}{2}  ] 520 *10^{-9}

=>   2 *  2 *   (2.8 *10^{-5}) = [m +  \frac{1}{2}  ] 520 *10^{-9}

=>    

       m = 215

given that we start counting m from zero

   it means that the number of  bright fringes that would appear is

         Z =  m + 1

=>    Z =  215 +1

=>     Z = 216 \ fringes

3 0
2 years ago
Archer shoots his arrow towards a target at a distance of 90 m and hits bullseye . Calculate the acceleration and time taken by
goldfiish [28.3K]

Answer:

acceleration = 45 m/s²

Time = 20 seconds

Explanation:

We are given;

Distance; s = 90m

Final velocity;v = 90 m/s

Since shot from rest, initial velocity;u = 0 m/s

So, to find the acceleration, we can use Newton's 2nd law of motion which is;

v² = u² + 2as

Where a is acceleration

Plugging in the values;

90² = 0² + 2a(90)

8100 = 180a

a = 8100/180

a = 45 m/s²

Now, for the time, we will use Newton's 1st law of motion which is;

v = u + at

Where t is time;

So;

90 = 0 + 4.5t

90 = 4.5t

t = 90/4.5

t = 20 seconds

3 0
2 years ago
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