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jonny [76]
3 years ago
6

Consider 2 steel rods, A and B, B has three times the area and twice the length of A, so young modulus of B will be what factor

times young modulus of A?
Physics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

  \frac{Y}{Y_o} = 2/3

Explanation:

The yuong modulus of a rod is defined as the relationship between the tensile strength and the strain

         Y =  \frac{ \frac{F}{A} }{\frac{\Delta L}{L_o} }

let's use the subscript "o" for rod A

         I = \frac{ \frac{F}{A_o} }{ \frac{\Delta L}{L_o} }

tells us that rod B has

         A = 3 A₀

         L = 2 L₀

we substitute

         Y = \frac{ \frac{F}{A} }{ \frac{\Delta L}{L} }

          Y = \frac{ \frac{F}{3A_o} }{ \frac{\Delta L}{ 2L_o}  }

         y = ⅔  \frac{ \frac{F}{A_o}}{ \frac{\Delta }{L_o} }

substituting the value of Y₀

          Y = ⅔  Y₀

           \frac{Y}{Y_o} = 2/3

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3 0
3 years ago
Read 2 more answers
What is the current I(3τ), that is, the current after three time constants have passed? The current in the circuit will approach
Olin [163]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

I(\tau)=0.051 A

b

I(3 \tau)=0.076 A

c

I_c= 0.08 A

Explanation:

From the question we are told that

                I(t) = \frac{e}{R}(1-e^{\frac{t}{\tau} }) ; \ Where \ \tau = L/R

From the question we are told to find I(\tau) when t=0  equals the time constant (\tau)

That is to obtain I(\tau).This  is mathematically represented as

                   I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{\tau}{\tau} })

             Substituting 12 V for \epsilon and 150Ω for R

                     I(\tau) = \frac{12}{150} (1- e^{-1})

                            =0.051 A

From the question we are told to find I(3 \tau) when t=0  equals the 3 times the  time constant (\tau)

That is to obtain I(3\tau).This  is mathematically represented as

                 I(\tau = t)  = \frac{\epsilon}{R} (1- e^{-\frac{3\tau}{\tau} })

                  I(\tau) = \frac{12}{150} (1- e^{-3})

                        =0.076 A

As tends to infinity \frac{\infty}{\tau}  = \infty

So I_c would be mathematically evaluated as

               I_c=I(\infty) = \frac{12}{150} (1- e^{- \infty})

                   = \frac{12}{150}

                   = 0.08 A

5 0
3 years ago
I’m still lost on this please help me on this I know it’s not D I got it wrong
RSB [31]

Before you even look at the questions, look over the graph, so you know what kind of information is there.

The x-axis is "time".  OK.  You know that as the graph moves from left to right, it shows what's happening as time goes on.

The y-axis is "speed" of something.  OK.  When the graph is high, the thing is moving fast.  When the graph is low, the thing is moving slow.  When the graph slopes up, the thing is gaining speed.  When the graph slopes down, the thing is slowing down.  When the graph is flat, the speed isn't changing, so the thing is moving at a constant speed.

NOW you can look at the questions.

OMG !  It's only ONE question:  What's happening from 'c' to 'd' ?  Well I don't know.  Perhaps we can figure it out if we LOOK AT THE GRAPH !

-- Between c and d, the graph is flat.  The speed is not changing.  It's the same speed at d as it was back at c .

What speed is it ?

-- Look back at the y-axis.  The speed at the height of c and d is 'zero' .

-- The 2nd and 4th choices are both correct.  From c to d, <em>the speed is constant</em>.  The constant speed is zero.  <em>The car is not moving</em>.

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3 years ago
20. GP A sinusoidal wave traveling in the negative x direction (to the left) has an amplitude of 20.0cm, a wavelength of 35.0cm,
umka21 [38]

The angular frequency of the wave is determined as 75.4 rad/s.

<h3>What is wave function?</h3>

A wave function is a mathematical equation for the motion of the wave.

y(x, t) = A sin(kx + ωt + Φ)

where;

  • ω is angular speed
  • k is angular wavenumber
  • Φ is phase angle

<h3>What is angular frequency?</h3>

The angular frequency is the angular displacement of any wave element per unit of time or the rate of change of the waveform phase.

<h3>Angular frequency</h3>

ω = 2πf

ω = 2π(12)

ω = 75.4 rad/s

Thus, the angular frequency of the wave is determined as 75.4 rad/s.

Learn more about angular frequency here: brainly.com/question/3654452

#SPJ4

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1 year ago
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sleet_krkn [62]

Answer:

Explanation:

Brownian motion is a random (irregular) motion of particles e.g smoke particle. The set up in the diagram can be used to observe the motion of smoke.

1. The apparatus used are:

A is a source of light

B is a converging lens

C is a glass smoke cell

D is a microscope

2. The uses of the apparatus are:

A - produces the light required to so as to see clearly the movement of the particles.

B - converges the rays of light from the source to the smoke cell.

C - is made of glass and used for encamping the smoke particles so as not to mix with air.

D - is used for the clear view or observation or study of the motion of the smoke particles in the cell.

4 0
3 years ago
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