Question

What is the molar mass of magnesium sulfate heptahydrate (MgSO4⋅ 7H2O) ?

Answer 1

Answer:

option D = 246 g/mol

Explanation:

Molar mass of MgSO₄⋅ 7H₂O:

Molar mass =  24.305 + 32.065 + 16×4 + 7 (1.008×2 +16)

Molar mass = 24.305 + 32.065 + 64 + 7 (18.016)

Molar mass =  24.305 + 32.065 +  64 + 126.112

Molar mass =  246.482 g /mol

Answer 2

Answer : The correct option is, 246 g/mol

Explanation :

Molar mass : It is defined as the mass in grams of one mole of substance and each element has its own unique molar mass. It is expressed in grams/mole or g/mol. It is equal to the mass of atom present in 1 mole.

Molar mass of Mg = 24 g/mole

Molar mass of S = 32 g/mole

Molar mass of O = 16 g/mole

Molar mass of H = 1 g/mole

Now we have to determine the molar mass of $MgSO_4.7H_2O$

$\text{Molar mass of }MgSO_4.7H_2O=\text{Molar mass of }Mg+\text{Molar mass of }S+11\times \text{Molar mass of }O+14\times \text{Molar mass of }H$

$\text{Molar mass of }MgSO_4.7H_2O=[24+32+11(16)+14(1)]=246g/mol$

Therefore, the molar mass of $MgSO_4.7H_2O$ is 246 g/mol