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3 years ago

What is the oxidation state of each element in COH2?

1 answer:

6 0

first of all will find for carbon
so x+(-2)+(1*2)=0.x=0
<span>carbon=0. </span>
<span>For oxygen it will b
;4+x+1*2=0,x=-6. </span>
<span>Oxygen=-6. and finally </span>
<span>For hydrogen; </span>
<span>4+(-2)+x*2=0;x=-1. </span>
<span>Hydrogen=-1.
</span>and the overall oxidation state of molecule is zeroo and it is a neutral compound

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1.3188g of antacid is weighed and mixed with 75.00 mL of excess 0.1746 M HCl. The excess wcid required 27.20 mL of 0.09767 M NaO

a_sh-v [17]

The amount of CaCO₃ in the tablet : 0.5219 g

<h3>Further explanation</h3>

Reaction

1. CaCO₃(in antacid) + 2HCl⇒ CaCl₂+H₂CO₃

2. Titration ⇒ HCl+NaOH⇒NaCl+H₂O

Reaction 2

For titration :

M₁V₁.n₁=M₂V₂n₂(n=acid/base valence⇒NaOH/HCl=1)

mol HCl=mol NaOH = excess HCl

$\tt 27.2\times 0.09767=2.657~mlmol$

Reaction 1

mol HCl

$\tt 75\times 0.1746=13.095~mlmol$

Moles of HCl used (reacted with CaCO₃) :

initial HCl - excess HCl =

$\tt 13.095-2.657=10.438~mlmol=0.010438~mol$

From reaction 1 :

mol HCl : mol CaCO₃ = 2 : 1

$\tt mol~CaCO_3=\dfrac{1}{2}\times 0.010438=0.005219$

mass of CaCO₃ :

$\tt 0.005219\times 100~g/mol=0.5219~g$

6 0

3 years ago

A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure

Lesechka [4]

Answer:

the final volume of the gas is $V_2$ = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure $P_{ext}$ :

$P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}$

$P_{ext} = 1.03 \ atm$

The workdone W = $P_{ext}$ V

The change in volume ΔV= $\dfrac{W}{P_{ext}}$

ΔV = $\dfrac{130.1 \ J \times \dfrac{1 \ L \ atm}{ 101.325 \ J} }{1.03 \ atm }$

ΔV = $\dfrac{1.28398717 }{1.03 }$

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial volume = 61.5 mL

The change in volume V is $\Delta V = V_2 -V_1$

$- V_2= - \Delta V -V_1$

multiply through by (-), we have:

$V_2= \Delta V+V_1$

$V_2$ = 1250 mL + 61.5 mL

$V_2$ = 1311.5 mL

∴ the final volume of the gas is $V_2$ = 1311.5 mL

5 0

3 years ago

Which of the fallowing elements is the most reactive?

Alexxx [7]

Which elements are most reactive?

The alkali metals, found in group 1 of the periodic table (formerly known as group IA), are very reactive metals that do not occur freely in nature. These metals have only one electron in their outer shell. Therefore, they are ready to lose that one electron in ionic bonding with other elements.

Fluorine is the most reactive

5 0

4 years ago

A voltaic cell is based on the following two half-reactions: ni 2(aq) 2e− → ni(s) e° = −0. 25 v cr 3(aq) 3e– → cr(s) e° = –0. 74

emmasim [6.3K]

The net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.

<h3>What is a half-cell reaction?</h3>

A half cell reaction is given as the oxidation or the reduction reaction that takes place at each of the anode or the cathode, forming the net redox reaction.

The cell potential and the half-reactions are:

Ni²⁺ + 2e⁻ = Ni (s) E° = -0.25 V

Cr³⁺ + 3e⁻ = Cr (s) E° = -0.74 V

The anodic reaction is given as:

Cr (s) = Cr³⁺ + 3e⁻ E° = 0.74 V

The cathodic reaction is given as:

Ni²⁺ + 2e⁻ = Ni (s) E° = -0.25 V

Thus, the net reaction of the cell will be:

3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s)

The cell potential can be calculated as:

E° = E (cathode) + E (anode)

E° = 0.74 + (-0.25) V

E° = 0.49 V

Thus, the net cell reaction is given as 3 Ni²⁺ (aq) + 2 Cr (s) = 2 Cr³⁺ (aq) + 3 Ni (s), and the cell potential is 0.49 V.

Learn more about cell potential, here:

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3 0

2 years ago

F O R 50 P O I N T S !!!

nika2105 [10]

Answer:

You would put the 4 quantum numbers corresponding to the electrons being described above

Explanation:

Quantum numbers refer to electrons, so I'll assume you mean the electron number that would correspond with the atomic number of the element. Quantum numbers are basically like an address for electrons, giving us information about the location of an electron from most general to most specific.

8 0

3 years ago