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xxMikexx [17]
3 years ago
5

PLS HELP ASAP I MARK BRAINLEST

Chemistry
1 answer:
german3 years ago
8 0
D. they are plants .
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An oxide and carbonate containing oxygen​
exis [7]

Answer:

example of carbonate containing oxygen :

  • CaCO3

( calcium carbonate having 3 atoms of oxygen )

example of oxide containing oxygen :

  • CO2

( carbon dioxide having 2 atoms of oxygen )

5 0
3 years ago
At constant temperature, if a gas occupies 312 mL at a pressure of 1.60 atm, what pressure is necessary for this gas to occupy a
inn [45]

Answer:

P₂ = 1.0 atm

Explanation:

Boyles Law problem => P ∝ 1/V at constant temperature (T).

Empirical equation

P ∝ 1/V => P = k(1/V) => k = P·V => for comparing two different case conditions, k₁ = k₂ => P₁V₁ = P₂V₂

Given

P₁ = 1.6 atm

V₁ = 312 ml

P₂ = ?

V₂ = 500 ml

P₁V₁ = P₂V₂ => P₂ = P₁V₁/V₂ =1.6 atm x 312 ml / 500ml = 1.0 atm

5 0
3 years ago
Determina el pH de una solución si la concentración de H es 3.5 x 10 molar, e indicar si es acido o bas
erastovalidia [21]

Answer:

Explanation:

IT'S FOR NOW, PLEASE DELIVER IT TODAY !!! I NEED HELP IT'S CHEMICAL WORK...

5 0
3 years ago
Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?.
Neko [114]

Molecules undergo London dispersion forces:

C_{4}H_{10} is the molecule will undergo only London dispersion forces when interacting with other molecules of the same kind.

What are London dispersion forces?

  • A sort of force that interacts between atoms and molecules that is often electrically symmetric is referred to as a London dispersion force.
  • When viewed from the nucleus, their electron distribution is frequently symmetrical. This dispersion force, which is also known as a transient attractive force, is frequently observed when the locations of the electrons in two nearby atoms cause the atoms to temporarily form dipoles.
  • The bond is polar when there are significant variations between the elements' electronegativities; it is nonpolar when there are similarities. When the molecule's dipole moment is equal to O, it is nonpolar; when it differs from O, it is polar.
  • The force at these molecules is known as the London dispersion force. In nonpolar molecules, the forces are weak, and partial charges must be induced so that they can bond. In polar molecules, partial charges caused by polarity result in a stronger link known as a dipole-dipole. The dipole-dipole is significantly stronger and known as a hydrogen bond if it is connected to a large electronegative atom (F, O, or N). Ionic force is the name for the attraction force at ionic substances.
  • The intermolecular force in the letter an is the London dispersion force because the compound is nonpolar;

<u>Reason for incorrect options:</u>

b: the compound is ionic because Na is a metal and the other part is covalent,

c: two compounds are possible: one is nonpolar and exhibits London dispersion force; the other is polar and exhibits dipole-dipole force; and

d: both compounds exhibit hydrogen bonds (H bonded to O, and H bonded to F).

NOTE: Your question is incomplete, but most probably your full question was, which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind?

A. C_{4}H_{10}

B. NaC_{2}H_{3}O_{2}

C. CH_{2}C_{12}

D. C_{2}H_{5}OH HF

Learn more about the London dispersion forces here,

brainly.com/question/22388709

#SPJ4

4 0
2 years ago
Suppose a 5.00 l sample of o2 at a given temperature and pressure contains 1.08
arsen [322]
Missing question: <span>A 5.00 L sample of O2 at a given temperature and pressure contains a 1.08x10^23 molecules. How many molecules would be contained in each of the following at the same temperature and pressure? </span>
a) 5.00 L H2.
<span>b) 5.00 L CO2.
Use </span>Avogadro's Law: The Volume Amount Law: <span>equal </span>volumes<span> of all gases, at the same temperature and pressure, have the same </span>number<span> of molecules. Because hydrogen and carbon(IV) oxide are gases, number of molecules are the same as number of oxygen molecules, so:
a) N(H</span>₂) = 1.08·10²³.
b) N(CO₂) = 1.08·10²³

5 0
3 years ago
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