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victus00 [196]
3 years ago
6

Which one of the following sets of units is appropriate for a second-order rate constant?A. s-1B. mol L-1 s-1C. L mol-1 s-1D. mo

l2 L-2 s-1E. L2 mol-2 s-1
Chemistry
1 answer:
Korolek [52]3 years ago
6 0

Answer:

E

Explanation:

A second order reaction is one in which the reaction rate is proportional to the concentrations of the 2 reactants. We only consider the reactants whose concentration are changing however.

For example, in the case:

A + B ----> C + D , provided that both A and B undergo concentration changes, the rate is proportional to the product of their concentrations.

Now, like we know, the unit of the reaction rate is per second I.e 1/s or simply s^-1 . Also it is important to note that the concentration of the reactants is exprested in units of mol/L. We can now mathematically calculate the unit of the rate constant.

Mathematically,

R = k × [A] [B]

Hence,

S^-1 = k × (mol/L)(mol/L)

S^

s^-1 = k × (mol/L)^2

K = s^-1 ÷ (mol/L)^2

K = s^-1 × L^2 × mol^-2.

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Rama09 [41]

Answer:

-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}

Explanation:

The rate law of a chemical reaction is given by

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This law can be written for any experiment, and making the quotient between those expressions the reaction orders can be found

Between experiments 1 and 2  

\frac{-r_{A1}}{{-r}_{A2}}=\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)^\beta

Then the expression for the calculation of \beta

\beta=\frac{ln\frac{-r_{A1}}{-r_{A2}}}{ln\left(\frac{\left[NH_3\right]_1}{\left[NH_3\right]_2}\right)}=\frac{ln\frac{0.2130}{0.1065}}{ln\left(\frac{0.250}{0.125}\right)}

Resolving  

\beta=1

Doing the same between experiments 3 and 4 the expression for \alpha is

\alpha=\frac{ln\frac{-r_{A3}}{-r_{A4}}}{ln\left(\frac{\left[BF_3\right]_3}{\left[BF_3\right]_4}\right)}=\frac{ln\frac{0.0682}{0.1193}}{ln\left(\frac{0.200}{0.350}\right)}

Resolving  

\alpha=1

This means that the rate law for this reaction is  

-r_{A}=k\times[BF_3]^{1}\times[NH_3]^{1}

5 0
3 years ago
compound of aspartame is a dipeptide that is often used as a sugar substitute which functional groups are present
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Answer:

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Explanation:

The functional groups present in the compound of aspartame are carboxyl, primary amine, amide, ester, and phenyl. Aspartame is an artificial non-saccharide sweetener which is 200 times sweeter than sucrose. This aspartame is commonly used as a sugar substitute in many foods and beverages. It has the trade names such as NutraSweet, Equal, and Canderel.

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ludmilkaskok [199]

Answer: Temperature is an example of a quantitative variable

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Temperature comes under interval scale , because interval scale has no zero point.

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Therefore , Temperature is an example of a quantitative variable.

Hence, the correct answer is "quantitative variable"

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