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galina1969 [7]
2 years ago
12

A drawer contains 6 red socks, 5 white socks and 9 blue socks. Without looking, you draw out a sock

Mathematics
1 answer:
umka2103 [35]2 years ago
3 0

Answer:

2/20

Step-by-step explanation:

because 9+5+6=20 and if you draw 2 red socks then that would be yur numerator

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A spherical fish bowl is half-filled with water. The center of the bowl is C and the length of segment AB is 16 inches as shown
NNADVOKAT [17]

Segment AB is a diameter of the sphere.

diameter = AB = 16 in.

radius = r = (16 in.)/2 = 8 in.


Volume of a sphere:


V = (4/3) * pi * r^3


V = (4/3) * (22/7) * (8 in.)^3


The water inside the bowl occupies half of the bowl, so the volume of the water is half the volume of the bowl.


Volume of water:


V = (1/2)(4/3)(22/7)(8^3) in.^3


Answer: Second choice.

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3 years ago
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On the coordinate plane below, quadrilaterals TRAP and HELP are similar to each other.
Aleks04 [339]

Answer:Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral

Step-by-step explanation:

6 0
2 years ago
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(a) Michael bought 19 pounds of sugar for $8. How many dollars did he pay per pound
Dmitrij [34]

Answer:

A = 2.37500

B = 8.5

Step-by-step explanation:

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Explanation B - 34 divided by 4 is 8.5

6 0
2 years ago
7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
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