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Alona [7]
3 years ago
6

A manufacturer is interested in the output voltage of a power supply used in a PC. Output voltage is assumed to be normally dist

ributed, with standard deviation 0.25 volt, and the manufacturer wishes to test volts against volts, using units. In your intermediate calculations, use z-scores rounded to two decimal places (e.g. 98.76).
(a) The acceptance region is_____. Find the value of a.
(b) Find the power of the test for detecting a true mean output voltage of 5.1 volts.
Mathematics
1 answer:
kompoz [17]3 years ago
4 0

Answer: hello your question was poorly written but i was able to the get missing parts online which enabled me resolve your question

answer:

a) a = 0.1096

b) 1.89 watts

Step-by-step explanation:

Std of output voltage = 0.25 volt

H0 : μ = 5 volts

Ha : μ ≠ 5 volts

n = 16

a) Acceptance region = 4.9 ≤ X ≤ 5.1  

Determine the value of a

value of a = 0.0548 + 0.0548

                 = 0.1096

<em>attached below is the reaming solution</em>

note : a is a type 1 error

b) power of test

True mean output voltage = 5.1 volts

P = - 1.89 watts

power cant be negative hence the power of the test  = 1.89 watts

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What is the solution set of these system5x-2y=17 and 4x-7=13?
MatroZZZ [7]

Answer:

x=5

y=4

Step-by-step explanation:

Step 1:

Let us solve for <em>x</em> using the 4x-7=13 equation by <u>isolating terms containing the variable</u>:

4x-7=13\\4x=20\\\fbox{x=5}

Great! <em>x</em> is 5... let's find <em>y</em>.

Step 2:

Since we know the value of <em>x</em>, we can use what we know to find <em>y</em> using the <u>other equation</u>:

5x-2y=17\\

<em>Given that x=5, we can </em><u><em>replace</em></u><em> x with 5</em>.

5*5-2y=17\\25-2y=17\\2y=8\\\\\fbox{y=4}

<em>I hope this helps! Let me know if you have any questions :)</em>

3 0
2 years ago
The length of the base of a rectangular prism is 9
Tatiana [17]

Answer:

The volume of the prism is <u>320 15/16 inches³</u>.

Step-by-step explanation:

Given:

The length of the base of a rectangular prism is 9 7/8.

The width of the prism is 8 1/8.

And the height is 4 inches.

Now, to find the volume of the prism.

(Length) <em> l = 9 7/8 = 79/8 inches.</em>

(Width)  <em> w = 8 1/8 = 65/8 inches</em>.

(Height)  <em>h = 4 inches</em>.

So, by putting the formula to get the volume:

Volume = w×h×l.

Volume=\frac{65}{8}\times 4\times \frac{79}{8}

Volume=320\frac{15}{16}

<em>Volume = 320 15/16 inches³.</em>

Therefore, the volume of the prism is 320 15/16 inches³.

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3 years ago
20x+32y=0 <br> -50x-80y=0
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Answer:

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Step-by-step explanation:

explain what you need

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liberstina [14]

Correct answer is A.

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

<h3>How to calculate the diameter?</h3>

If you know the radius of the circle, multiply by 2 to get the diameter. The radius is the distance from the center of the circle to the edge. For example, if the radius of a circle is 4 cm, then the diameter is 4 cm x 2 = 8 cm. If you know the circumference of the circle, divide by π to get the diameter.

<h3>Briefing:</h3>

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction which is A.

The diameter of the circle is used for the square as l=2r therefore corresponds to the diameter, while for a hexagon r=r being the radius of the circle.

To know more about Diameter visit:

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I understand that the question you are looking for is:

Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.

A) The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

B) The radius of the circle is used for the square construction, but the diameter of the circle is used for the regular hexagon construction.

C) The square will need two arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

D) The square will need six arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

7 0
1 year ago
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